|M| 谁帮我简写这一段string代码

Question

string ticketCount1; //成人票数量
                    string ticketCount2; //成人票数量
                    string ticketCount3; //成人票数量
                    string ticketCount4; //成人票数量
                    string ticketCount5; //成人票数量
if (dr["TicketCount"].ToString() != "1")
                    {
                        ticketCount1 = "NFILL";
                    }
                    else
                    {
                        ticketCount1 = "FILL";
                    }
                    if (dr["TicketCount"].ToString() != "2")
                    {
                        ticketCount2 = "NFILL";
                    }
                    else
                    {
                        ticketCount2 = "FILL";
                    }
                    if (dr["TicketCount"].ToString() != "3")
                    {
                        ticketCount3 = "NFILL";
                    }
                    else
                    {
                        ticketCount3 = "FILL";
                    }
                    if (dr["TicketCount"].ToString() != "4")
                    {
                        ticketCount4 = "NFILL";
                    }
                    else
                    {
                        ticketCount4 = "FILL";
                    }
                    if (dr["TicketCount"].ToString() != "5")
                    {
                        ticketCount5 = "NFILL";
                    }
                    else
                    {
                        ticketCount5 = "FILL";
                    }谢谢
这样写太长了有没有短的,最好用数组

Answer 1

string[] ticketCount = new string[5];//成人票数量
for (int i = 0; i < 5; i++)
{
if (dr["TicketCount"].ToString() != (i + 1).ToString())
{
ticketCount[i] = "NFILL";
}
else
{
ticketCount[i] = "FILL";
}
}

Answer 2

string ticketCount1 = "NFILL"; //成人票数量
string ticketCount2 = "NFILL"; //成人票数量
string ticketCount3 = "NFILL"; //成人票数量
string ticketCount4 = "NFILL"; //成人票数量
string ticketCount5 = "NFILL"; //成人票数量
switch(dr["TicketCount"].ToString())
{
    case "1":
        ticketCount1 = "FILL";
        break;
    case "2":
        ticketCount2 = "FILL";
        break;
    case "3":
        ticketCount3 = "FILL";
        break;
    case "4":
        ticketCount4 = "FILL";
        break;
    case "5":
        ticketCount5 = "FILL";
        break;
}

Answer 3

string[] ticketCount=new string[6]; //成人票数量
for(int i=1;i<=5;i++){
  if(dr["TicketCount"].ToString() !=i.ToString()){
    ticketCount[i] = "NFILL";
}
  else{
   ticketCount[i]= "FILL";
}
}

Answer 4

string ticketCount1 = "NFILL"; //成人票数量
string ticketCount2 = "NFILL"; //成人票数量
string ticketCount3 = "NFILL"; //成人票数量
string ticketCount4 = "NFILL"; //成人票数量
string ticketCount5 = "NFILL"; //成人票数量
switch(dr["TicketCount"].ToString())
{
    case "1":
        ticketCount1 = "FILL";
        break;
    case "2":
        ticketCount2 = "FILL";
        break;
    case "3":
        ticketCount3 = "FILL";
        break;
    case "4":
        ticketCount4 = "FILL";
        break;
    case "5":
        ticketCount5 = "FILL";
        break;
}
---------------------------------
  同意!
  case 比if快,结构也清晰

Answer 5

string ticketCount1 = "NFILL"; //成人票数量
string ticketCount2 = "NFILL"; //成人票数量
string ticketCount3 = "NFILL"; //成人票数量
string ticketCount4 = "NFILL"; //成人票数量
string ticketCount5 = "NFILL"; //成人票数量
switch(dr["TicketCount"].ToString())
{
    case "1":
        ticketCount1 = "FILL";
        break;
    case "2":
        ticketCount2 = "FILL";
        break;
    case "3":
        ticketCount3 = "FILL";
        break;
    case "4":
        ticketCount4 = "FILL";
        break;
    case "5":
        ticketCount5 = "FILL";
        break;
}
---------------------------------
  同意!
  最优方案