xsl问题，急

Question

怎么查找<Axes>/<Axis name="Axis0" >/<Tuples>/<Tuple>/<Caption>
另外得到<Axes>/<Axis name="Axis1" >下有几个<Tuples></Tuples>循环
<Axes>
  <Axis name="Axis0" >
    <Tuples>
      <Tuple>
          <Member Hierarchy="[学生].[学生]" >
          <UName>[学生].[学生].&[方法法] </UName>
          <Caption>方法法 </Caption>
          <LName>[学生].[学生].[学生] </LName>
          <LNum>1 </LNum>
          <DisplayInfo>0 </DisplayInfo>
        </Member>
      </Tuple>
      <Tuple>
        <Member Hierarchy="[学生].[学生]" >
          <UName>[学生].[学生].&[何文良] </UName>
          <Caption>何文良 </Caption>
          <LName>[学生].[学生].[学生] </LName>
          <LNum>1 </LNum>
          <DisplayInfo>131072 </DisplayInfo>
        </Member>
      </Tuple>
      <Tuple>
        <Member Hierarchy="[学生].[学生]" >
          <UName>[学生].[学生].&[后果后] </UName>
          <Caption>后果后 </Caption>
          <LName>[学生].[学生].[学生] </LName>
          <LNum>1 </LNum>
          <DisplayInfo>131072 </DisplayInfo>
        </Member>
      </Tuple>
      <Tuple>
        <Member Hierarchy="[学生].[学生]" >
          <UName>[学生].[学生].&[克林顿] </UName>
          <Caption>克林顿 </Caption>
          <LName>[学生].[学生].[学生] </LName>
          <LNum>1 </LNum>
          <DisplayInfo>131072 </DisplayInfo>
        </Member>
      </Tuple>
      <Tuple>
        <Member Hierarchy="[学生].[学生]" >
          <UName>[学生].[学生].&[刘铭江] </UName>
          <Caption>刘铭江 </Caption>
          <LName>[学生].[学生].[学生] </LName>
          <LNum>1 </LNum>
          <DisplayInfo>131072 </DisplayInfo>
        </Member>
      </Tuple>
      <Tuple>
        <Member Hierarchy="[学生].[学生]" >
          <UName>[学生].[学生].&[往往外] </UName>
          <Caption>往往外 </Caption>
          <LName>[学生].[学生].[学生] </LName>
          <LNum>1 </LNum>
          <DisplayInfo>131072 </DisplayInfo>
        </Member>
      </Tuple>
    </Tuples>
  </Axis>
  <Axis name="Axis1" >
    <Tuples>
      <Tuple>
        <Member Hierarchy="[班级].[班级]" >
          <UName>[班级].[班级].&[数学] </UName>
          <Caption>数学 </Caption>
          <LName>[班级].[班级].[班级] </LName>
          <LNum>1 </LNum>
          <DisplayInfo>0 </DisplayInfo>
        </Member>
      </Tuple>
      <Tuple>
        <Member Hierarchy="[班级].[班级]" >
          <UName>[班级].[班级].&[英语] </UName>
          <Caption>英语 </Caption>
          <LName>[班级].[班级].[班级] </LName>
          <LNum>1 </LNum>
          <DisplayInfo>131072 </DisplayInfo>
        </Member>
      </Tuple>
      <Tuple>
        <Member Hierarchy="[班级].[班级]" >
          <UName>[班级].[班级].&[语文] </UName>
          <Caption>语文 </Caption>
          <LName>[班级].[班级].[班级] </LName>
          <LNum>1 </LNum>
          <DisplayInfo>131072 </DisplayInfo>
        </Member>
      </Tuple>
    </Tuples>
  </Axis>
</Axes>

Answer 1

你这是xml吧,
不是xsl,xsl是有语法的,比如<xsl:value-of select="/channel/title"/>什么的如果是xml,你可以这样
XmlDocument rssDoc = new XmlDocument();
rssDoc.Load(rssStream);单个结点
XmlNode rss = rssDoc.SelectSingleNode("rss/channel/title");
if (rss != null)
  title = rss.InnerText;结点列表
XmlNodeList rssItems = rssDoc.SelectNodes("rss/channel/item");
你可以循环rssItems 

Answer 2

主要是XmlDocument 的两个方法
SelectSingleNode
SelectNodes