初学.net,所以在写一个留言版的程序。。在“修改”这里出现了问题。。我是用FP来编写界面。<asp:EditCommandColumn ButtonType="LinkButton" UpdateText="更新" HeaderText="修改" CancelText="取消" EditText="编辑"></asp:EditCommandColumn>这句的地方,在FP的“设计”界面显示这个错误:错误 - value cannot be null.parameter name:child调试程序时不会显示出来的怎么解决
<table border="1" width="98%" cellspacing="0" cellpadding="0" id="table4" height="200">
<tr>
<td width="179" rowspan="3">
<p align="center"><img border="0" src="face/<%#DataBinder.Eval(Container.DataItem,"gb_sex")%>.gif" width="32" height="32"><p align="center">
Name:<%#DataBinder.Eval(Container.DataItem,"gb_name")%></td>
<td height="25">
<div align="center">
<table border="0" width="98%" cellspacing="0" cellpadding="0" id="table5">
<tr>
<td><%#DataBinder.Eval(Container.DataItem,"gb_title")%></td>
</tr>
</table>
</div>
</td>
</tr>
<tr>
<td valign="top">
<div align="center">
<table border="0" width="98%" cellspacing="0" cellpadding="0" id="table6" height="100">
<tr>
<td valign="top"><%# DataBinder.Eval(Container.DataItem,"gb_content")%></td>
</tr>
</table>
</div>
</td>
</tr>
<tr>
<td height="25">
<div align="center">
<table border="0" width="98%" cellspacing="0" cellpadding="0" id="table7">
<tr>
<td><asp:EditCommandColumn ButtonType="LinkButton" UpdateText="更新" HeaderText="修改" CancelText="取消" EditText="编辑"></asp:EditCommandColumn></td> <============这行!!
</tr>
</table>
</div>
</td>
</tr>
</table>
<br>
</Itemtemplate></asp:Repeater>