如何为这个xml编写一个xslt

Question

1.xml
<person>
   <name>李</name>
   <age>32</age>
   <sex>男</sex>
<person>
如何分别显示name,age,sex内容？
这个xslt如何编写？
谢谢！

Answer 1

XML:
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="test.xsl" ?>
<ROOT>
<PARAM NAME="ALBUM_ID" VALUE="36713" />
<PARAM NAME="MV_ID" VALUE="123" />
<PARAM NAME="ALBUM_IMG" VALUE="fffff.jpg" />
</ROOT>XSL:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" />
<xsl:template match="ROOT">
<table border="1">
<tr>
<td>ID</td>
<td>NAME</td>
<td>VALUE</td>
</tr>
<xsl:apply-templates select="PARAM" />
</table>
</xsl:template>
<xsl:template match="PARAM">
<tr>
<td><xsl:number value="position()" /></td>
<td><xsl:value-of select="@NAME" /></td>
<td><xsl:value-of select="@VALUE" /></td>
</tr>
</xsl:template>
</xsl:stylesheet>

Answer 2

楼上这位说的很好
可是，我的xml和你的稍微有点不同呀！
请问，我的上面的那个xml如何读取呀？

Answer 3

<ea:FieldList TableName="Table1" Style="Normal">
<ea:FieldItem>
<ea:FieldName>name</ea:FieldName>
<ea:FieldDisplayName>姓名</ea:FieldDisplayName
<ea:Length>50</ea:Length>
<ea:IsTwoColumn>true</ea:IsTwoColumn>
<ea:CodeTable>user</ea:CodeTable>
</ea:FieldItem>
<ea:FieldItem>
<ea:FieldName>age</ea:FieldName>
<ea:FieldDisplayName>年龄</ea:FieldDisplayName
<ea:Length>50</ea:Length>
<ea:IsTwoColumn>true</ea:IsTwoColumn>
<ea:CodeTable>user</ea:CodeTable>
</ea:FieldItem>
<ea:FieldItem>
<ea:FieldName>sex</ea:FieldName>
<ea:FieldDisplayName>性别</ea:FieldDisplayName
<ea:Length>50</ea:Length>
<ea:IsTwoColumn>true</ea:IsTwoColumn>
<ea:CodeTable>user</ea:CodeTable>
</ea:FieldItem>
</ea:FieldList>