XML 存数据

Question

主食:米饭  这个是从数据库中读出的 我想帮它存在一个XML 文件里  如何分解  谢谢
- <CanList>
  <CanName>早餐</CanName> 
- <SelectFoods>
- <ClassList>
  <ClassName>主食</ClassName> 
- <FoodsList>
  <Food>米饭</Food> 
  </FoodsList>
  </ClassList>
  </SelectFoods>
  </CanList>

Answer 1

分解什么、？
用ds.WriteXml()不行么

Answer 2

<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/css" href="t.xsl"?>
<myxml xmlns:xsi="http:www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http:www.w3.org/2001/XMLSchema">
  <root>
    <CanList>
      <CanFoods1>主食:米饭 主食:米饭 荤菜: 烩鸭四宝   糖粘羊尾   白汁鱼肚  素菜: 麻婆豆腐   麻婆豆腐  汤菜: 一品豆腐汤  主食:米饭 荤菜:鸡蛋  糖粘羊尾   枸杞牛鞭汤  素菜:苦菜 苦菜 汤菜: 一品豆腐汤  </CanFoods1>
    </CanList>
  </root>
</myxml>
这个是我用XML 保存后得到的啊  我想要的是这样的效果 
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/css" href="t.xsl"?>
<myxml xmlns:xsi="http:www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http:www.w3.org/2001/XMLSchema">
 <root>
  - <CanList>
  <CanName>早餐</CanName>  
- <SelectFoods>
- <ClassList>
  <ClassName>主食</ClassName>  
- <FoodsList>
  <Food>米饭</Food>  
  </FoodsList>
  </ClassList>
  </SelectFoods>
  </CanList> </root>
</myxml>

Answer 3

            string XmlString;
            System.Xml.XmlDocument xml = new System.Xml.XmlDocument();
            xml.LoadXml(XmlString);
            xml.Save(string.Format("{0}\\abc.xml", path));

Answer 4

            string XmlString;
            System.Xml.XmlDocument xml = new System.Xml.XmlDocument();
            xml.LoadXml(XmlString);
            xml.Save(string.Format("{0}\\abc.xml", path));