筛选在Grid绑定的数据源进行。
DataTable dt;
dt.Select("条件");
DataTable dt;
dt.Select("条件");
解决方案 »
- 修改错误提示的问题
- 望论坛的前辈们给点建议
- url rewirte 中文乱码
- 如何用程序登录一个网站?
- 图片以二进制在数据库中存取、生成静态页面、与html的交换
- 用存储过程写的分页,怎么在gridview上显示上一页,下一页
- <%# 在用insert into 插入到SQL数据库后,再读出来在网页中按html语言显示的时候要怎么处理SQL语句 ----------------------------------
- StreamReader问题~~~~~~~~~~~~~~~~~~~help!
- 如何讲一个文本文件转化为pdf文件
- 如何建立自己的DataGrid页脚.
- 拜师了:asp.net入门
- 发现.net的bug??
在DataList的每一行中用FindControl,查找DataGrid,将正确的数据分别和DataGrid分别邦定。
关键是现在根本找不到label的值,很郁闷,不知道思路对不对!
在DataList1控件中查找label1控件,找到后,转换为Label控件,最后提取Text属性值即可。
using System;
using System.Collections;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Web;
using System.Web.SessionState;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.HtmlControls;namespace WebApplication1
{
/// <summary>
/// Summary description for WebForm17.
/// </summary>
public class WebForm17 : System.Web.UI.Page
{
protected System.Web.UI.WebControls.DataList DataList1;
private void Page_Load(object sender, System.EventArgs e)
{
// Put user code to initialize the page here
this.DataList1.DataSource = this.bind().DefaultView;
this.DataList1.DataBind();
} #region Web Form Designer generated code
override protected void OnInit(EventArgs e)
{
//
// CODEGEN: This call is required by the ASP.NET Web Form Designer.
//
InitializeComponent();
base.OnInit(e);
}
/// <summary>
/// Required method for Designer support - do not modify
/// the contents of this method with the code editor.
/// </summary>
private void InitializeComponent()
{
this.Load += new System.EventHandler(this.Page_Load); }
#endregion private DataTable bind()
{
DataTable dt = new DataTable();
dt.Columns.Add("Item",typeof(string));
dt.Columns.Add("Type",typeof(int));
DataRow dr; //= new DataRow();
for(int i = 1;i< 5;i++)
{
dr = dt.NewRow();
dr[0] = "Item" + i.ToString();
if(i%2 == 0)
dr[1] = 2;
else
dr[1] = 1;
dt.Rows.Add(dr);
} return dt;
} public DataTable getGridData(string type)
{
DataTable dt = this.bind();
DataTable odt = new DataTable();
odt.Columns.Add("Type",typeof(int));
DataRow odr;
foreach(DataRow dr in dt.Rows)
{
if(dr["type"].ToString() == type)
{
odr = odt.NewRow();
odr[0] = Convert.ToInt32(type);
odt.Rows.Add(odr);
}
}
return odt; }
}
}。aspx code
<%@ Page language="c#" Codebehind="WebForm17.aspx.cs" AutoEventWireup="false" Inherits="WebApplication1.WebForm17" %>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" >
<HTML>
<HEAD>
<title>WebForm17</title>
<meta name="GENERATOR" Content="Microsoft Visual Studio .NET 7.1">
<meta name="CODE_LANGUAGE" Content="C#">
<meta name=vs_defaultClientScript content="JavaScript">
<meta name=vs_targetSchema content="http://schemas.microsoft.com/intellisense/ie5">
</HEAD>
<body MS_POSITIONING="GridLayout"> <form id="Form1" method="post" runat="server">
<asp:DataList id="DataList1" runat="server">
<ItemTemplate>
<asp:Label id="Label1" runat="server" ><%#(DataBinder.Eval(Container.DataItem,"item")).ToString()%></asp:Label>
<asp:DataGrid id="DataGrid1" runat="server" DataSource='<%#getGridData((DataBinder.Eval(Container.DataItem,"Type")).ToString())%>'></asp:DataGrid>
</ItemTemplate>
</asp:DataList> </form> </body>
</HTML>