asp.net中怎么算出当前是第几周呀

Question

请参考Calendar.GetWeekOfYear Method

Answer 1

/// <summary>
/// 返回一个数组长度为3的字符串数组
/// </summary>
/// <returns>GetWeekDay[0]=周次;GetWeekDay[1]=该周第一天;GetWeekDay[2]=该周最后一天</returns>
public string[] GetWeekDay()
{
string[] inti = new string[3];
DateTime day = DateTime.Parse(DateTime.Today.Year + "-1-1");
System.DayOfWeek dateTime = day.DayOfWeek;
int DayCount = DateTime.Today.DayOfYear;
int i = ( DayCount + aa( dateTime ) -2 ) / 7 + 1;
inti[0] = i.ToString();inti[1] = day.AddDays( DayCount -1 ).ToString("yyyy年MM月dd日");
inti[2] = day.AddDays( DayCount + 5 ).ToString("yyyy年MM月dd日");return inti;
}

Answer 2

参考
using System;
using System.Globalization;
public class SamplesCalendar  {   public static void Main()  {      // Gets the Calendar instance associated with a CultureInfo.
      CultureInfo myCI = new CultureInfo("en-US");
      Calendar myCal = myCI.Calendar;      // Gets the DTFI properties required by GetWeekOfYear.
      CalendarWeekRule myCWR = myCI.DateTimeFormat.CalendarWeekRule;
      DayOfWeek myFirstDOW = myCI.DateTimeFormat.FirstDayOfWeek;      // Displays the number of the current week relative to the beginning of the year.
      Console.WriteLine( "The CalendarWeekRule used for the en-US culture is {0}.", myCWR );
      Console.WriteLine( "The FirstDayOfWeek used for the en-US culture is {0}.", myFirstDOW );
      Console.WriteLine( "Therefore, the current week is Week {0} of the current year.", myCal.GetWeekOfYear( DateTime.Now, myCWR, myFirstDOW ));      // Displays the total number of weeks in the current year.
      DateTime LastDay = new System.DateTime( DateTime.Now.Year, 12, 31 );
      Console.WriteLine( "There are {0} weeks in the current year ({1}).", myCal.GetWeekOfYear( LastDay, myCWR, myFirstDOW ), LastDay.Year );   }}

Answer 3

int i = ( DayCount + aa( dateTime ) -2 ) / 7 + 1;
这个中的aa是什么意思呀？

Answer 4

不好意思，忘了写了，只是一个显示星期的函数
private int aa( System.DayOfWeek weekday )
{
switch ( weekday.ToString() )
{
case "Sunday" :
return 1;
case "Monday":
return 2;
case "Tuesday":
return 3;
case "Wednesday":
return 4;
case "Thursday":
return 5;
case "Friday":
return 6;
case "Saturday":
return 0;
default:
return 8;
} }