求助!

Question

二叉树第6个节点下面有几个节点OR-MAING的几种用法，具体用ASP。NET中，用户输入1234567.01234转换为大写的壹贰叁肆伍陆柒。零壹贰叁肆，而且，允许正负可达亿位，并且不可出错（用C#的语言来实现）

Answer 1

GOOGLE或BAIDU
这里不应该是伸手就能获得知识的。

Answer 2

using System;
using System.Collections.Generic;
using System.Text;namespace ConsoleApplication2
{
    class Program
    {
        static void Main(string[] args)
        {
            string show_Str = ""; 
            string Str = "1234567.01234";
            string[] Arr = Str.Split('.');
            
            int Str_dawei=Arr[0].Length;            for (int i = 0; i < Arr[0].Length; i++) 
            {
                show_Str += Program.shuzi(int.Parse(Arr[0].Substring(i,1))) + Program.danwei(Str_dawei);
                Str_dawei = Str_dawei - 1;
            }
            if (Str.IndexOf('.') > -1) 
            {
                show_Str += "点";
                for (int j = 0; j < Arr[1].Length; j++) 
                {
                    show_Str += Program.shuzi(int.Parse(Arr[1].Substring(j, 1)));
                }            }            System.Console.Write(show_Str);
            System.Console.ReadLine();
        }
        public static string danwei(int Str_Length) 
        {
            string Re_Str="";
            switch (Str_Length)
            {
                case 1:
                    Re_Str= "";
                    break;
                case 2:
                    Re_Str=  "十";
                    break;
                case 3:
                    Re_Str= "百";
                    break;
                case 4:
                   Re_Str= "千";
                    break;
                case 5:
                    Re_Str=  "万";
                    break;
                case 6:
                    Re_Str=  "十";
                    break;
                case 7:
                    Re_Str= "百";
                    break;
                case 8:
                    Re_Str= "千";
                    break;
                case 9:
                   Re_Str= "亿";
                    break;
                default:
                    Re_Str = "";
                    break;
              
                   
            }
            return Re_Str;
        }
        public static string shuzi(int Str_shuzi)
        {
            string Re_Str = "";
            switch (Str_shuzi)
            {
                case 0:
                    Re_Str = "零";
                    break;
                case 1:
                    Re_Str = "壹";
                    break;
                case 2:
                    Re_Str = "贰";
                    break;
                case 3:
                    Re_Str = "叁";
                    break;
                case 4:
                    Re_Str = "肆";
                    break;
                case 5:
                    Re_Str = "伍";
                    break;
                case 6:
                    Re_Str = "陸";
                    break;
                case 7:
                    Re_Str = "柒";
                    break;
                case 8:
                    Re_Str = "捌";
                    break;
                case 9:
                    Re_Str = "玖";
                    break;
                default:
                    Re_Str = "";
                    break;
               
            }
            return Re_Str;
            
        }
    }
}

Answer 3

string nums = "1234567.01234";
        string Nums = "零壹贰叁肆伍陆柒捌玖";
        StringBuilder newnums = new StringBuilder("");
        foreach (char s in nums)
        {
            if (s != '.' && s != '-')
            {
                newnums.Append(Nums[int.Parse(s.ToString())]);
            }
            else
            {
                newnums.Append(s);
            }
        }
期待更好的，应该是尽量减少程序复杂度。