如何将数据生成这样的xml格式

Question

在bcb和Delphi中可以直接用ado控件把数据集转换为一种xml格式，
<xml xmlns:s='uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882'
xmlns:dt='uuid:C2F41010-65B3-11d1-A29F-00AA00C14882'
xmlns:rs='urn:schemas-microsoft-com:rowset'
xmlns:z='#RowsetSchema'>
<s:Schema id='RowsetSchema'>
<s:ElementType name='row' content='eltOnly' rs:updatable='true'>
<s:AttributeType name='id' rs:number='1' rs:nullable='true' rs:writeunknown='true' rs:basecatalog='ceshi' rs:basetable='test'
 rs:basecolumn='id'>
<s:datatype dt:type='string' rs:dbtype='str' dt:maxLength='10' rs:fixedlength='true'/>
</s:AttributeType>
<s:AttributeType name='name' rs:number='2' rs:nullable='true' rs:writeunknown='true' rs:basecatalog='ceshi'
 rs:basetable='test' rs:basecolumn='name'>
<s:datatype dt:type='string' rs:dbtype='str' dt:maxLength='10' rs:fixedlength='true'/>
</s:AttributeType>
<s:AttributeType name='descrip' rs:number='3' rs:nullable='true' rs:writeunknown='true' rs:basecatalog='ceshi'
 rs:basetable='test' rs:basecolumn='descrip'>
<s:datatype dt:type='string' rs:dbtype='str' dt:maxLength='10' rs:fixedlength='true'/>
</s:AttributeType>
<s:extends type='rs:rowbase'/>
</s:ElementType>
</s:Schema>
<rs:data>
<z:row id='12        ' name='122       ' descrip='122       '/>
<z:row id='21        ' name='234       ' descrip='456       '/>
<z:row id='34324     ' name='54        ' descrip='788       '/>
</rs:data>
</xml>
跪求各位大大，asp.net有什么方法能直接这样生成吗

Answer 1

查出一个dataset  来  传到下面这个方法中；   然后用 StringBuilder 接收；在以text/XML  形式输出就行了；   页面源文件 只留第一行   其他的全删；public static  StringBuilder jkf( DataSet dt)
    {
       
            DataSet ds = dt;
            StringBuilder sb = new StringBuilder();
            sb.Append("<?xml version=\"1.0\" encoding=\"utf-8\" ?> ");
            sb.Append("<authors>");
            for (int i = 0; i < ds.Tables[0].Rows.Count; i++)
            {
                sb.Append("<author>");
                DataRow dr = ds.Tables[0].Rows[i];
                for (int j = 0; j < ds.Tables[0].Columns.Count; j++)
                {
                    string colname = ds.Tables[0].Columns[j].ColumnName;                    sb.AppendFormat("<{0}>{1}</{2}>", colname, dr[colname].ToString(), colname);
                }                sb.Append("</author>");
            }
            sb.Append("</authors>");
          
            return sb;
        }

Answer 2

各位大哥，我想要的是我发的那个xml格式，不是这个·····

Answer 3

使用XmlConvert类参考:C#中将DataSet的内容写成XML

Answer 4

这是个?DataSet ds = new DataSet();
string xml1 = ds.GetXml();
string xml2 = ds.GetXmlSchema();