格式化字符串

Question

RT。我现有一字符串如下：ABCDFGEWJDJDKDJSDJSJDJSDJJD,现在我想从第10个字符以后显示成*号。如何实现？

Answer 1

先用subString截取出前10个字符
后面的就可以用循环剩下的字符数生成*号 拼接到后面

Answer 2

 string s = "ABCDFGEWJDJDKDJSDJSJDJSDJJD";
                
   string s1=s.Length>10?s.Substring(10):"";
   s = s.Replace(s1, new string('*', s1.Length));
   Response.Write(s); //ABCDFGEWJD***************** 

Answer 3

 public string subStr()
        {
            string str = "adsadfjksl;fdskfjskdl;fjssfsfsf";//要格式的字符串
            int len = str.Length;//取字符串长度
            if (len> 10)
            {
                str = str.Substring(0, 10);//截取前10个
                for (int i = 0; i < len - 10; i++)
                {
                    str += "*";//剩下的循环为"*"
                }
            }
            return str;
        }测试可用

Answer 4

1:
string str="ABCDFGEWJDJDKDJSDJSJDJSDJJD";
if(str.Length>20)
    str = str.SubString(0,20)+"*";
Console.WriteLine(str);
//ABCDFGEWJDJDKDJSDJSJ*
2:
string str="ABCDFGEWJDJDKDJSDJSJDJSDJJD";
str = Regex.Replace(str, "(?<=[A-Z]{20}[A-Z]*)[A-Z]","*");
//ABCDFGEWJDJDKDJSDJSJ*******

Answer 5

               string s = "ABCD";
                
                string s1=s.Length>10?s.Substring(10):"";
                if (s1.Length > 0)  //加个if判断，防止s长度小于10
                {
                    s = s.Replace(s1, new string('*', s1.Length));
                }
                Response.Write(s); //ABCD

Answer 6

string str = "ABCDFGEWJDJDKDJSDJSJDJSDJJD";
char[] chars = str.ToCharArray();
StringBuilder sb = new StringBuilder();
for(int i=0;i<chars.Count;i++)
{
   if(i<10)
   {
      sb.Append(chars[i]);
   }
   else
   {
      sb.Append("*");
   }
}
string newstr = sb.ToString();