关于字符串删除

Question

str=12212[sdfgdfgdgfsdf]dfdf[aa33454edffgs443]fdfdff[aa333]我想删除所有中括号中间的所有字符，不论长短。str=12212[]dfdf[]fdfdff[]这个是我要的答案，请问如何实现？

Answer 1

大致思路：先把str转换成为一个char类型的数组，定义一个stringbuilder，然后遍历char类型的数组，符合条件的添加到stringbuilder中

Answer 2

用Regexp替换\[.*\]为[]。using System.Text.RegularExpressions;class TestApp
{
static string GetReplace(Match m) 
{
    return "[]";
}static Main(string[] Args)
{
string text = "12212[sdfgdfgdgfsdf]dfdf[aa33454edffgs443]fdfdff[aa333]";
string result = Regex.Replace(text, @"\[.*\]",
         new MatchEvaluator(TestApp.GetReplace));
Console.WriteLine(result);
}
}

Answer 3

            string str = "12212[sdfgdfgdgfsdf]dfdf[aa33454edffgs443]fdfdff[aa333]";
            string result = System.Text.RegularExpressions.Regex.Replace(str, @"\[[^\[\]]*\]", "[]");
            Console.WriteLine(result);

Answer 4

static void Main(string[] args)
        {
            string str;
            str="12212[sdfgdfgdgfsdf]dfdf[aa33454edffgs443]fdfdff[aa333]";
            char[] c = str.ToCharArray();
            int length = c.Length;
            StringBuilder sb = new StringBuilder();
            for (int i = 0; i < length; i++)
            {
                sb.Append(c[i]);
                if (c[i]=='[')
                {
                    while (c[i]!=']')
                    {
                        i++;
                    }
                    sb.Append(']');
                }
            }
            Console.WriteLine(sb.ToString());
            Console.ReadKey();
        }

Answer 5

 string str = "12212[sdfgdfgdgfsdf]dfdf[aa33454edffgs443]fdfdff[aa333]";
        string result = System.Text.RegularExpressions.Regex.Replace(str, @"(?<=\[)[^\[]+(?=\])", "");
        Response.Write(result);

Answer 6

string Filter(string s)
        {
            string filtered = string.Empty;
            char[] tmp = s.ToCharArray();
            bool flag = false;
            for (int i = 0; i < tmp.Length; i++)
            {
                
                if (tmp[i] == ']' && flag)
                {
                    flag = false;
                }
                if (!flag)
                {
                    filtered += tmp[i].ToString();
                }
                if (tmp[i] == '[' && !flag)
                {
                    flag = true;
                }
            }
            return filtered;
        }
汗自己一个

Answer 7

 string str = "12212[sdfgdfgdgfsdf]dfdf[aa33454edffgs443]fdfdff[aa333]";
        string result = System.Text.RegularExpressions.Regex.Replace(str, @"(?<=\[)[^\[]+(?=\])", "");
        Response.Write(result);这个可以

Answer 8

str = Regex.Replace(str, @"\[[^\]]*\]", "[]");

Answer 9

用正则表达式 最方便！
这东西头疼，具体自已搜索！下面以个笨办法：
string returnValue = "";
string[] a = str.Split('[');
        string[] b = new string[2];
        for (int i = 0; i < a.Length; i++)
        {
            b = a[i].Split(']');
            if (b.Length == 1)
            {
                returnValue += b[0] +"[]";
            }
            else
            {
                returnValue += b[1] + "[]";
            }
        }
    
        returnValue = returnValue.Substring(0, returnValue.Length - 2);