RadioButtonList的OnSelectedIndexChanged事件能不能不刷新页面

Question

非常郁闷 由于表单比较长,执行了RadioButtonList的OnSelectedIndexChanged事件总是刷回到页头 有什么办法不刷新 或者 刷新后还回到原来的位置么?

Answer 1

放在Ajax的UpdatePanel控件里

Answer 2

autopostback设成false，但这样你后台事件就触发不了了，如果你想回后台处理的，又不要页面不刷新的，请用AJAX

Answer 3

能给个例子么 本来没用过ajax

Answer 4

页面代码<asp:RadioButtonList ID="RadioButtonList1" runat="server" RepeatDirection="Horizontal" AutoPostBack="True" OnSelectedIndexChanged="RadioButtonList1_SelectedIndexChanged">
              <asp:ListItem Selected="True" Value="1">订 金</asp:ListItem>
              <asp:ListItem Value="0">完 款</asp:ListItem>
              <asp:ListItem Value="2">退 订</asp:ListItem>
</asp:RadioButtonList>对应的.cs文件里的方法protected void RadioButtonList1_SelectedIndexChanged(object sender, EventArgs e)
    {
        string temp = RadioButtonList1.SelectedValue.ToString();
        if (temp.Equals("1"))//订金
        {
            tb_wankuanDate.Visible = false;
            lb_wankuanDate.Text = tb_wankuanDate.Text;
            tb_tuidingDate.Visible = false;
            lb_tuidingDate.Text = tb_tuidingDate.Text;
        }
        else if (temp.Equals("0"))//完款
        {
            tb_wankuanDate.Visible = true;
            lb_wankuanDate.Text = "";
            tb_tuidingDate.Visible = false;
            lb_tuidingDate.Text = tb_tuidingDate.Text;
        }
        else if (temp.Equals("2"))//退订
        {
            tb_wankuanDate.Visible = false;
            lb_wankuanDate.Text = tb_wankuanDate.Text;
            tb_tuidingDate.Visible = true;
            lb_tuidingDate.Text = "";
        }
    }
楼上各位说的UpdatePanel应该怎么加呢?

Answer 5

回到原來位置的腳本
if (document.all)
{
    window.attachEvent("onload",function(){LoadWinScrollCookie();})
    window.attachEvent("onunload",function(){SetWinScrollCookie();})
}
else
{
    window.addEventListener("load",function(){LoadWinScrollCookie();},false);
    window.addEventListener("unload",function(){SetWinScrollCookie();},false);
}function SetWinScrollCookie()
{
    document.cookie="scrollTop="+document.body.scrollTop;
    document.cookie="scrollLeft="+document.body.scrollLeft;
}function LoadWinScrollCookie()
{
    var allcookies=document.cookie;
    if(allcookies!=null)
    {
        var pos=allcookies.indexOf("scrollTop=");
        if(pos!=-1)
        {
            var start=pos+10;
            var end=allcookies.indexOf(";",start);
            if(end==-1) end=allcookies.length;
            var value=allcookies.substring(start,end);
            value=unescape(value);
            document.body.scrollTop=value;
        }
        pos=allcookies.indexOf("scrollLeft=");
        if(pos!=-1)
        {
            var start=pos+11;
            var end=allcookies.indexOf(";",start);
            if(end==-1) end=allcookies.length;
            var value=allcookies.substring(start,end);
            value=unescape(value);
            document.body.scrollLeft=value;
        }
    }
}

Answer 6

<asp:UpdatePanel ID="UpDatePanle1" runat="server">
<asp:RadioButtonList ID="RadioButtonList1" runat="server" RepeatDirection="Horizontal" AutoPostBack="True" OnSelectedIndexChanged="RadioButtonList1_SelectedIndexChanged">
              <asp:ListItem Selected="True" Value="1">订 金</asp:ListItem>
              <asp:ListItem Value="0">完 款</asp:ListItem>
              <asp:ListItem Value="2">退 订</asp:ListItem>
</asp:RadioButtonList>
</asp:UpdatePanel>差不多就这个意思了

Answer 7

我遇到的情况是，把RadioButton放到UpdatePanel里，AutoPostBack设置为True，仍然会刷新页面，郁闷中，大家能不能  把既能执行 OnSelectedIndexChanged ，又能防止页面刷新 的方法？期待中