求：这样的函数该怎么写？（没有接触过函数，请各位大侠帮帮忙啊！）

Question

例如 string a="6565start1234566endtrtert34startrereterend44645"
输入起始字符和结束字符 start 和 end
最后得到一个数组arr
arr[0]=” 1234566”
arr[1]=” rereter”

Answer 1

是个是字符串处理的吧，Replace的吧；

Answer 2

Regex reg = new Regex(@"start(?<num>\d+)end");
reg.Match(s).Groups["num"].Value;

Answer 3

好像不是repalce的，总之是一个字符串处理的，以某字符分断并存为数组我几过好像在查询用得比较多，好像是多词查词，

Answer 4

string a="6565start1234566endtrtert34startrereterend44645"
貌似有点麻烦，分数太少，不值

Answer 5

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;namespace JQuerWeb
{
    public class SubStringFromStartEnd
    {
        public SubStringFromStartEnd()
        { }        public IList<String> GetSubStringsBetweenStartAndEnd(String a)
        {
            int startIndex, endIndex;
            IList<string> lists = new List<string>();
            while (true)
            {
                startIndex = -1;
                endIndex = -1;
                startIndex = a.IndexOf("start");
                endIndex = a.IndexOf("end");
                if (startIndex >= endIndex)
                {
                    break;
                }
                string result = a.Substring(startIndex + 5, endIndex - startIndex - 5);
                lists.Add(result);
                a = a.Substring(endIndex + 3);
            }
            return lists;
        }
    }
}string a = "6565start1234566endtrtert34startrereterend44645";
            SubStringFromStartEnd subStringFromStartEnd = new SubStringFromStartEnd();
          IList<String> lists=  subStringFromStartEnd.GetSubStringsBetweenStartAndEnd(a);
          foreach (String item in lists)
          {
              Response.Write(item+"<br/>");
          }

Answer 6

试试2楼的正则吧。就是匹配字符串中start开头end结尾中的字符串

Answer 7

给出一段测试的代码： [TestMethod]
        public void TestGetSubStringsBetweenStartAndEnd()
        {
            string a = "6565start1234566endtrtert34startrereterend44645";
            SubStringFromStartEnd subStringFromStartEnd = new SubStringFromStartEnd();
            IList<String> lists = subStringFromStartEnd.GetSubStringsBetweenStartAndEnd(a);
            Assert.IsTrue(lists.Count == 2);
            Assert.AreEqual("1234566", lists[0]);
            Assert.AreEqual("rereter", lists[1]);
            a = "start123end";
            lists=subStringFromStartEnd.GetSubStringsBetweenStartAndEnd(a);
            Assert.IsTrue(lists.Count == 1);
            Assert.AreEqual("123", lists[0]);
            a = "startend";
            lists = subStringFromStartEnd.GetSubStringsBetweenStartAndEnd(a);
            Assert.AreEqual(0, lists.Count);
            a = "start123";
            lists = subStringFromStartEnd.GetSubStringsBetweenStartAndEnd(a);
            Assert.AreEqual(0, lists.Count);
            a = "start";
            lists = subStringFromStartEnd.GetSubStringsBetweenStartAndEnd(a);
            Assert.AreEqual(0, lists.Count);
            a = "123end";
            lists = subStringFromStartEnd.GetSubStringsBetweenStartAndEnd(a);
            Assert.AreEqual(0, lists.Count);
            a = "end";
            lists = subStringFromStartEnd.GetSubStringsBetweenStartAndEnd(a);
            Assert.AreEqual(0, lists.Count);
            a = "endstart";
            lists = subStringFromStartEnd.GetSubStringsBetweenStartAndEnd(a);
            Assert.AreEqual(0, lists.Count);
            a = "end123start";
            lists = subStringFromStartEnd.GetSubStringsBetweenStartAndEnd(a);
            Assert.AreEqual(0, lists.Count);
            a = "end123start456";
            lists = subStringFromStartEnd.GetSubStringsBetweenStartAndEnd(a);
            Assert.AreEqual(0, lists.Count);
        }all pass

Answer 8

不好意思，上面的代码有点错误，现在给你另一份通过测试的代码: public IList<String> GetSubStringsBetweenStartAndEnd(String a)
        {
            int startIndex, endIndex;
            IList<string> lists = new List<string>();
            while (true)
            {
                startIndex = -1;
                endIndex = -1;
                startIndex = a.IndexOf("start");
                endIndex = a.IndexOf("end");
                if ((startIndex >= endIndex) || (startIndex==-1 && endIndex>=0))
                {
                    break;
                }
                string result = a.Substring(startIndex + 5, endIndex - startIndex - 5);
                if (result != null && result.Length > 0)
                {
                    lists.Add(result);
                }
                a = a.Substring(endIndex + 3);
            }
            return lists;
        }2楼的方法是正则，楼主可以尝试一下，如果行的话（我没测试2楼的正则），可以考虑，代码写的也很简单，清爽。

Answer 9

string a="6565start1234566endtrtert34startrereterend44645"
string[] Array=a.split(new string[]{'start','end'});
试试、、、

Answer 10

// 还是帮你回答一下吧
例如 string a="6565start1234566endtrtert34startrereterend44645"
string b = a.Replace("start","#");
string[] c = a.split(new char[]{'#'});
ArrayList list = new ArrayList();
// 在这里判断c中的每项是否包含end
foreach(string tmp in c)
{
   int endIndex = tmp.IndexOf("end");
   if(endIndex > 0)
   {
      // list是ArrayList,请在循环外自己定义
      list.add(tmp.substring(0,endIndex); 
   }
}
/*好家伙，累死我了....*/

Answer 11

// 还是帮你回答一下吧
例如 string a="6565start1234566endtrtert34startrereterend44645"
string b = a.Replace("start","#");
string[] c = a.split(new char[]{'#'});
ArrayList list = new ArrayList();
// 在这里判断c中的每项是否包含end
foreach(string tmp in c)
{
   int endIndex = tmp.IndexOf("end");
   if(endIndex > 0)
   {
      // list是ArrayList,请在循环外自己定义
      list.add(tmp.substring(0,endIndex); 
   }
}
/*好家伙，累死我了....*/

Answer 12

// 刚才有一句废话，现在注释掉了
例如 string a="6565start1234566endtrtert34startrereterend44645"
//string b = a.Replace("start","#");
string[] c = a.split(new string[]{"start"});
ArrayList list = new ArrayList();
// 在这里判断c中的每项是否包含end
foreach(string tmp in c)
{
   int endIndex = tmp.IndexOf("end");
   if(endIndex > 0)
   {
      // list是ArrayList,请在循环外自己定义
      list.add(tmp.substring(0,endIndex); 
   }
}
/*好家伙，累死我了....*/

Answer 13

先用Replace("start")替换成单个字符（&） 然后结合Split分割函数进行循环分割。