string str ="1,2,3,4,5";
怎么变成
int 的1,2,3,4,5啊?
谢谢!!C#的!
怎么变成
int 的1,2,3,4,5啊?
谢谢!!C#的!
解决方案 »
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foreach(string s in ary)
{
response.write(s)
int v=int.paser(s)
}
string[] values = str.Split(',');
List<int> results = new List<int>();
foreach (string v in values)
{
try
{
results.Add(Convert.ToInt32(v));
}
catch (Exception)
{
}
}
string[] s = str.Split(',');
int[] i = s.Select(j => Convert.ToInt32(j)).ToArray<int>();
string str = "1,2,3,4,5";
string[] strList = str.Split(',');
List<int> nums = new List<int>();
for (int i = 0; i < strList.Length; i++)
{
nums.Add(int.Parse(strList[i].ToString()));
}
using System.Text.RegularExpressions;
string str="aaajsbbbjsccc";
string[] sArray=Regex.Split(str,"js",RegexOptions.IgnoreCase);
foreach (string i in sArray) Response.Write(i.ToString() + "<br>");
输出结果:
aaa
bbb
ccc
2、用多个字符来分隔:
string str="aaajbbbscccjdddseee";
string[] sArray=str.Split(new char[2] {'j','s'});
foreach(string i in sArray) Response.Write(i.ToString() + "<br>");
输出结果:
aaa
bbb
ccc
ddd
eee
3、用单个字符来分隔:
string str="aaajbbbjccc";
string[] sArray=str.Split('j');
foreach(string i in sArray) Response.Write(i.ToString() + "<br>");
输出结果:
aaa
bbb
ccc
////////////////////////////////////////////////
string[] arr = str.Split("o");
这是一个具有语法错误的语句,Split 的 separator 参数应该是 char[] 或 string[],不应是字符串。正确的示例:string str = "technology";
char[] separator = { 'o' };
string[] arr = str.Split(separator);
////////////////////////////////////////////////////String.Split 方法有6个重载函数:
程序代码
1) public string[] Split(params char[] separator)
2) public string[] Split(char[] separator, int count)
3) public string[] Split(char[] separator, StringSplitOptions options)
4) public string[] Split(string[] separator, StringSplitOptions options)
5) public string[] Split(char[] separator, int count, StringSplitOptions options)
6) public string[] Split(string[] separator, int count, StringSplitOptions options) 下边我们通过一些实例来说明下怎么使用(以下string words = "1,2.3,,4";):
1. public string[] Split(params char[] separator)
程序代码
string[] split = words.Split(new Char[] { ',' });//返回:{"1","2.3","","4"}
string[] split = words.Split(new Char[] { ',', '.' });//返回:{"1","2","3","","4"}
2. public string[] Split(char[] separator, int count)ITPUB个人空间,n:H!C0M/S3U\u0002P
程序代码
string[] split = words.Split(new Char[] { ',', '.' }, 2);//返回:{"1","2.3,,4"}
string[] split = words.Split(new Char[] { ',', '.' }, 6);//返回:{"1","2","3","","4"}
3. public string[] Split(char[] separator, StringSplitOptions options)
程序代码
string[] split = words.Split(new Char[] { ',', '.' }, StringSplitOptions.RemoveEmptyEntries);//返回:{"1","2","3","4"} 不保留空元素
string[] split = words.Split(new Char[] { ',', '.' }, StringSplitOptions.None);//返回:{"1","2","3","","4"} 保留空元素
4. public string[] Split(string[] separator, StringSplitOptions options)
程序代码
string[] split = words.Split(new string[] { ",", "." }, StringSplitOptions.RemoveEmptyEntries);//返回:{"1","2","3","4"} 不保留空元素
\u0002w1I+Ch%^\u0017}0string[] split = words.Split(new string[] { ",", "." }, StringSplitOptions.None);//返回:{"1","2","3","","4"} 保留空元素
5. public string[] Split(char[] separator, int count, StringSplitOptions options)
程序代码
string[] split = words.Split(new Char[] { ',', '.' }, 2, StringSplitOptions.RemoveEmptyEntries);//返回:{"1","2.3,,4"} 不保留空元素ITPUB个人空间1K;e\u0007f\u0008f }\u0011C n
string[] split = words.Split(new Char[] { ',', '.' }, 6, StringSplitOptions.None);//返回:{"1","2","3","","4"} 保留空元素
6. public string[] Split(string[] separator, int count, StringSplitOptions options)
程序代码
string[] split = words.Split(new string[] { ",", "." }, 2, StringSplitOptions.RemoveEmptyEntries);//返回:{"1","2.3,,4"} 不保留空元素
string[] split = words.Split(new string[] { ",", "." }, 6, StringSplitOptions.None);//返回:{"1","2","3","","4"} 保留空元素
需要注意的是没有重载函数public string[] Split(string[] separator),所以我们不能像VB.NET那样使用words.Split(","),而只能使用words.Split(',')
先多看点书吧
string[] strList = str.Split(',');
List<int> nums = new List<int>();
for (int i = 0; i < strList.Length; i++)
{
nums.Add(int.Parse(strList[i].ToString()));
}
string[] strList = str.Split(',');
List<int> nums = new List<int>();
for (int i = 0; i < strList.Length; i++)
{
nums.Add(int.Parse(strList[i].ToString()));
}