DataContractJsonSerializer序列化问题

Question

 public string GetPensonList() {
            List<Penson> plist =new List<Penson>{ new Penson{ Saddress="湖南", Sage=20, Sname="张三"},
                               new Penson{ Saddress="湖南长沙", Sage=30, Sname="李四"}
                             };
          
            DataContractJsonSerializer ser=new DataContractJsonSerializer(typeof(List<Penson>));
            MemoryStream ms=new MemoryStream();
            ser.WriteObject(ms,plist);
            string json = System.Text.Encoding.UTF8.GetString(ms.ToArray());
            ms.Close();
            return json;        
        } [Serializable]   
    public class Penson {      
        public string Sname { get; set; }      
        public string Saddress { get; set; }    
        public int Sage { get; set; }
    }   $.ajax({
                 type: 'POST',
                 contentType: 'application/json',
                 url: 'GetPenson.asmx/GetPensonList',
                 dataType: 'json',
                 success: function (data) {
                    
                     var str = '';
                     $(data.d).each(function () {
                        
                         str += this['Saddress'];
                     });
                     $("#result").append(str);                 }
             });
返回的DATA 不知道怎么 this['Saddress'] 

Answer 1

string Serialize<T>(T data)
  {
  System.Runtime.Serialization.Json.DataContractJsonSerializer serializer =
new System.Runtime.Serialization.Json.DataContractJsonSerializer(data.GetType());
  using (MemoryStream ms =
new MemoryStream())
  {
  serializer.WriteObject(ms, data);
  return Encoding.UTF8.GetString(ms.ToArray());
  }
  }  
Response.Write("{\"success\":\"0\",\"msg\":\"密码错误\"}");
http://blog.csdn.net/lee576/archive/2009/01/08/3736880.aspx