熟悉正则表达的高手指点：如何替换字符串中的回车符

Question

String ss=".....";
ss=ss.Replace("\r","");

Answer 1

可以用replace來實現.
Function format(formatdata)
formatdata=replace(formatdata,"&","&")
      'formatdata=replace(formatdata,"'","''")  
    formatdata=replace(formatdata,"<","&lt;")
    formatdata=replace(formatdata,">","&gt;")
    formatdata=replace(formatdata,"chr(60)","&lt;")
    formatdata=replace(formatdata,"chr(37)","&gt;")
    formatdata=replace(formatdata,"""","&quot;")
      'formatdata=replace(formatdata,";",";;")    
    formatdata=replace(formatdata,chr(13),"<br>" & chr(13)+chr(10))
    format=replace(formatdata,chr(32),"&nbsp;")
End Function

Answer 2

我需要的是把
abc
123
的字符串变成abc123中间没有回车符的

Answer 3

上面的人太差了，其实是用
chr=Regex.Replace(chr,@"[\w\W][\n]","",RegexOptions.IgnoreCase);

Answer 4

是吗？？？？
str=str.Replace("\r\n","")
这个不行吗？