遍历一个list 如何给Datatable的行进行赋值呢？

Question

   各位大神好，小弟现在要做一个小功能，例如用户输入一组随机数据，个数不定，如“111112212121111122222”这样的一组数据，通过拆分，放到datatagridview里面去，每列的行数只是4个而已，如果相邻的数超过了4个，那么就在后一行补足，效果如下图

Answer 1

 private void button1_Click(object sender, EventArgs e)
        {
            string numberStr = textBox1.Text.Trim();   //接收用户输入的数据
            string temp = string.Empty;               //定义变量temp
            string column = string.Empty;             //定义变量column
            List<string> lstColumn = new List<string>();            DataTable table = new DataTable();         //定义一个临时table
            DataColumn dcolumn;                        //定义列
            DataRow row;                               //定义行             row = table.NewRow();
            table.Rows.Add(row);                        numberStr.ToCharArray().ToList().ForEach((char c) =>
            {
                if (string.IsNullOrEmpty(temp))
                {
                    temp = c.ToString();
                }                if (temp == c.ToString())
                {
                    column += c;
                }
                else
                {
                    lstColumn.Add(column);
                    temp = c.ToString();
                    column = temp;
                }
            });
            lstColumn.Add(column);
            //遍历LstColumn  为table的列赋值            int id = 0;
            foreach (var item in lstColumn)
            {
                id++;
                if (item.Length <= 4)      //判断item的长度
                {
                    dcolumn = new DataColumn();
                    dcolumn.ColumnName = id.ToString();
                    table.Columns.Add(dcolumn);
                }
                else
                {
                    dcolumn = new DataColumn();
                    dcolumn.ColumnName = id.ToString();
                    table.Columns.Add(dcolumn);
                }
            }
            //遍历列，对列中的数据赋值到行中
            foreach (var item in lstColumn)
            {
                int i = 0;//                foreach (var subItem in item)
                {
                    int j = 0;
                    table.Rows[j][i] = subItem.ToString();
                    j++;
                }
                i++;            }           
            dg.DataSource = table;        }    }
}
            这是小弟自己写的源码，但是效果不出来，请各位大神指点，谢谢

Answer 2

给dt赋值你只要知道dt.row[i]["colname"]=....

Answer 3

111112212121111122222
变
11111，22，1，2，12，11111，22222char [] c = 111112212121111122222.toCharArray();
string out=null;
string in = null;
fro(int i = 0; i<c,lengthi++)
{
if(c==0)
out=c[i]
else 
out=c[i-1];
if(c[i]==out)
in+=c[i]
else
in+=','
}
---
当前字符与过去的不一样就加一个逗号吧他们分开这时in就是11111，22，1，2，12，11111，22222
————
string in[] = in.spilt(',')
这时in就是11111][22][1][2][12][11111][22222]
然后每个数组取得模数
in[i],lengthi%4
1为例子，得到1
这时候你的单元就是当前列加1列，赋值就写循环吧手写的我意思就这样，你在改一下，有时间给你写全

Answer 4

in[i],lengthi%4
1为例子，得到1
如果in[i].length % 4  有余数呢？那么就该怎么加？

Answer 5

 private void button1_Click(object sender, EventArgs e)
        {
            string numberStr = textBox1.Text.Trim();   //接收用户输入的数据
            string temp = string.Empty;               //定义变量temp
            string column = string.Empty;             //定义变量column
            List<string> lstColumn = new List<string>();            DataTable table = new DataTable();         //定义一个临时table
            DataColumn dcolumn;                        //定义列
            DataRow row;                               //定义行             row = table.NewRow();
            table.Rows.Add(row);            numberStr.ToCharArray().ToList().ForEach((char c) =>
            {
                if (string.IsNullOrEmpty(temp))
                {
                    temp = c.ToString();
                }                if (temp == c.ToString())
                {
                    column += c;
                }
                else
                {
                    lstColumn.Add(column);
                    temp = c.ToString();
                    column = temp;
                }
            });
            lstColumn.Add(column);
            //遍历LstColumn  为table的列赋值
            int id = 0;
            foreach (var item in lstColumn)
            {
                id++;
                dcolumn = new DataColumn();
                dcolumn.ColumnName = id.ToString();
                table.Columns.Add(dcolumn);
                if (item.Length > 4)      //判断item的长度
                {
                    int consult = 0;   //余数
                    int quotient = Math.DivRem(item.Length, 4, out consult);
                    if (consult != 0)
                    {
                        for (int k = 0; k < quotient; k++)
                        {
                            id = id + k;
                        }
                        id++;
                        dcolumn = new DataColumn();
                        dcolumn.ColumnName = id.ToString();
                        table.Columns.Add(dcolumn);
                    }
                    else
                    {
                        dcolumn = new DataColumn();
                        dcolumn.ColumnName = id.ToString();
                        table.Columns.Add(dcolumn);
                    }
                }
            }
            //遍历列，对列中的数据赋值到行中            int i = 0;
            foreach (var item in lstColumn)
            {
                int j = 0;
                foreach (var subItem in item)
                {
                    table.Rows[j][i] = subItem.ToString();
                    row = table.NewRow();
                    table.Rows.Add(row);                    if (j == 3)
                    {
                        j = 0;
                        i++;
                    }
                    else j++;
                }
                i++;
            }
            dg.DataSource = table;
        }
代码我修改了，然后现在出现了一个问题，  相邻的数字 如果输入相同的数超过了8个，就会报错  错误信息是：无法找到列 2