简单解析JSON

Question

我有下面一个字符串的JSON：我想获得那三个参数所对应的三个值，要怎么实现{"type":"1061.jpg","EmployeeID":"c32df9b4-dd3b-46c5-8387-329b76356641","TaskID":"e52df9b4-ee3b-46c5-8387-329b76356641"}

Answer 1

refer: http://blog.csdn.net/chinacsharper/article/details/9246627

Answer 2

引用neNewtonsoft.Json.dll，上面的链接有。
 public class TT
    {
        public string Type { get; set; }
        public string EmployeeID { get; set; }
        public string TaskID { get; set; }
    }
static void Main(string[] args)
        {
            string json = "[{\"type\":\"1061.jpg\",\"EmployeeID\":\"c32df9b4-dd3b-46c5-8387-329b76356641\",\"TaskID\":\"e52df9b4-ee3b-46c5-8387-329b76356641\"}]";
            List<TT> list = JsonConvert.DeserializeObject<List<TT>>(json);            foreach (TT info in list)
            {
                Console.WriteLine("type:" + info.Type + "\r\n EmployeeID:" + info.EmployeeID + "\r\n TaskID:" + info.TaskID);
            }
        }

Answer 3

for( key in data)
{
  
}