在线求正则

Question

<img  src=http://image4.suning.cn/content/catentries/00000000010380/000000000103809183/fullimage/000000000103809183_9.jpg src2=http://image2.suning.cn/content/catentries/00000000010380/000000000103809183/fullimage/000000000103809183_9f.jpg alt="">求正则分别获取src2 src 的路径正则

Answer 1

(?i)<img\b[^>]*?src=(['"]?)(?<src>\S+?)\1\ssrc2=\1(?<src2>\S+?)\1[^>]*?>

Answer 2

(?i)<img\b[^>]*?src=(['"]?)(?<src>\S+?)\1\ssrc2=\1(?<src2>\S+?)\1\s[^>]*?>

Answer 3

如果src或 src2的顺序不定的话，可以这样来写：Regex reg=new Regex(@"(?i)<img(?=[^>]*?src=(['""]?)(?<src>\S+?)\1\s)[^>]*?src2=\1(?<src2>\S+?)\1\s[^>]*?>")

Answer 4

Groups["src"] 取src的值
Groups["src2"] 取src2的值