asp.net 解析xml

Question

<?xml version="1.0" encoding="UTF-8"?>
<WorkSheetContent>
  <WorkSheetData>
    <WorkSheetNo>111111111111111</WorkSheetNo>
    <ProjName>95199</ProjName>
    <DelType>1</DelType>
    <EnvFlg>O</EnvFlg>
    <ProgTypeNo>0</ProgTypeNo>
    <ServiceNo>0</ServiceNo>
    <ClassFlg>T</ClassFlg>
    <OccurDate>20090819093000</OccurDate>
    <DataOperType>D</DataOperType>
    <WorkDesc>95199 update 20090817</WorkDesc>
    <SuporProc>dsfdsf</SuporProc>
    <Attatchments>
    </Attatchments>
    <DeadLine>20090820173000</DeadLine>
    <TradeCode>1000900011</TradeCode>
    <OrgCode>123456789012</OrgCode>
    <CustomsCode>5300</CustomsCode>
    <OrgName>北京企业</OrgName>
    <CustName>李四</CustName>
    <DistrictCode>1021</DistrictCode>
    <Extension>681184</Extension>
    <TelePhone>65194135</TelePhone>
    <Mobile>667046</Mobile>
    <FaxDistrictCode>4544</FaxDistrictCode>
    <FaxExtension>5456</FaxExtension>
    <Fax>4415665</Fax>
    <Email>
    </Email>
    <Note>
    </Note>
  </WorkSheetData>
  <DeptNo>5300</DeptNo>
  <SignData>dsfs</SignData>
</WorkSheetContent>

Answer 1

 XmlDocument doc = new XmlDocument();
 doc.LoadXml(strXML.Trim());
 就是如何操作doc获得所有节点的值

Answer 2

 protected void Page_Load(object sender, EventArgs e)
        {
            string xml = @"<?xml version=""1.0"" encoding=""UTF-8""?> 
<WorkSheetContent> 
  <WorkSheetData> 
    <WorkSheetNo>111111111111111 </WorkSheetNo> 
    <ProjName>95199 </ProjName> 
    <DelType>1 </DelType> 
    <EnvFlg>O </EnvFlg> 
    <ProgTypeNo>0 </ProgTypeNo> 
    <ServiceNo>0 </ServiceNo> 
    <ClassFlg>T </ClassFlg> 
    <OccurDate>20090819093000 </OccurDate> 
    <DataOperType>D </DataOperType> 
    <WorkDesc>95199 update 20090817 </WorkDesc> 
    <SuporProc>dsfdsf </SuporProc> 
    <Attatchments> 
    </Attatchments> 
    <DeadLine>20090820173000 </DeadLine> 
    <TradeCode>1000900011 </TradeCode> 
    <OrgCode>123456789012 </OrgCode> 
    <CustomsCode>5300 </CustomsCode> 
    <OrgName>北京企业 </OrgName> 
    <CustName>李四 </CustName> 
    <DistrictCode>1021 </DistrictCode> 
    <Extension>681184 </Extension> 
    <TelePhone>65194135 </TelePhone> 
    <Mobile>667046 </Mobile> 
    <FaxDistrictCode>4544 </FaxDistrictCode> 
    <FaxExtension>5456 </FaxExtension> 
    <Fax>4415665 </Fax> 
    <Email> 
    </Email> 
    <Note> 
    </Note> 
  </WorkSheetData> 
  <DeptNo>5300 </DeptNo> 
  <SignData>dsfs </SignData> 
</WorkSheetContent> ";            System.Xml.XmlDocument dom = new System.Xml.XmlDocument();
            dom.LoadXml(xml);
            foreach (System.Xml.XmlNode node in dom.ChildNodes)
            {   
                if(node.Name !="xml")
                Response.Write(GetNodeText(node)+"<BR>");
                 
            }             
        }        string GetNodeText(System.Xml.XmlNode node)
        {
            string str = node.InnerText;
            if (node.HasChildNodes)
            {
                str = "";
                foreach (System.Xml.XmlNode n in node.ChildNodes)
                {
                    str += GetNodeText(n);
                }
                str += "<BR>";
            }
            return str;
        }

Answer 3

我的意思是：
string WorkSheetNo =
string ProjName =

Answer 4

 string xml = @"<?xml version=""1.0"" encoding=""UTF-8""?> 
<WorkSheetContent> 
  <WorkSheetData> 
    <WorkSheetNo>111111111111111 </WorkSheetNo> 
    <ProjName>95199 </ProjName> 
    <DelType>1 </DelType> 
    <EnvFlg>O </EnvFlg> 
    <ProgTypeNo>0 </ProgTypeNo> 
    <ServiceNo>0 </ServiceNo> 
    <ClassFlg>T </ClassFlg> 
    <OccurDate>20090819093000 </OccurDate> 
    <DataOperType>D </DataOperType> 
    <WorkDesc>95199 update 20090817 </WorkDesc> 
    <SuporProc>dsfdsf </SuporProc> 
    <Attatchments> 
    </Attatchments> 
    <DeadLine>20090820173000 </DeadLine> 
    <TradeCode>1000900011 </TradeCode> 
    <OrgCode>123456789012 </OrgCode> 
    <CustomsCode>5300 </CustomsCode> 
    <OrgName>北京企业 </OrgName> 
    <CustName>李四 </CustName> 
    <DistrictCode>1021 </DistrictCode> 
    <Extension>681184 </Extension> 
    <TelePhone>65194135 </TelePhone> 
    <Mobile>667046 </Mobile> 
    <FaxDistrictCode>4544 </FaxDistrictCode> 
    <FaxExtension>5456 </FaxExtension> 
    <Fax>4415665 </Fax> 
    <Email> 
    </Email> 
    <Note> 
    </Note> 
  </WorkSheetData> 
  <DeptNo>5300 </DeptNo> 
  <SignData>dsfs </SignData> 
</WorkSheetContent> ";            System.Xml.XmlDocument dom = new System.Xml.XmlDocument();
            dom.LoadXml(xml);             
            System.Xml.XmlNode node = dom.SelectSingleNode("//ProjName");
            if (node != null)
            {
                Response.Write(node.InnerText);
            }