这语文……
string[] s={"11","22","33"};
string a="22";
int i,count=s.Length;
for(i=0;i<count;i++)
{
if(s[i].Equals(a))
break;
}
// i就是你要的
// 上一个为s[i-1]
// 下一个为s[i+1]
// 注意判断越界
string[] s={"11","22","33"};
string a="22";
int i,count=s.Length;
for(i=0;i<count;i++)
{
if(s[i].Equals(a))
break;
}
// i就是你要的
// 上一个为s[i-1]
// 下一个为s[i+1]
// 注意判断越界
{
public static void Main()
{
string[] dinosaurs = { "Compsognathus",
"Amargasaurus", "Oviraptor", "Velociraptor",
"Deinonychus", "Dilophosaurus", "Gallimimus",
"Triceratops" }; Console.WriteLine();
foreach(string dinosaur in dinosaurs)
{
Console.WriteLine(dinosaur);
} Console.WriteLine(
"\nArray.FindIndex(dinosaurs, EndsWithSaurus): {0}",
Array.FindIndex(dinosaurs, EndsWithSaurus)); Console.WriteLine(
"\nArray.FindIndex(dinosaurs, 2, EndsWithSaurus): {0}",
Array.FindIndex(dinosaurs, 2, EndsWithSaurus)); Console.WriteLine(
"\nArray.FindIndex(dinosaurs, 2, 3, EndsWithSaurus): {0}",
Array.FindIndex(dinosaurs, 2, 3, EndsWithSaurus));
} // Search predicate returns true if a string ends in "saurus".
private static bool EndsWithSaurus(String s)
{
if ((s.Length > 5) &&
(s.Substring(s.Length - 6).ToLower() == "saurus"))
{
return true;
}
else
{
return false;
}
}
}/* This code example produces the following output:Compsognathus
Amargasaurus
Oviraptor
Velociraptor
Deinonychus
Dilophosaurus
Gallimimus
TriceratopsArray.FindIndex(dinosaurs, EndsWithSaurus): 1Array.FindIndex(dinosaurs, 2, EndsWithSaurus): 5Array.FindIndex(dinosaurs, 2, 3, EndsWithSaurus): -1
*/
*****************************************************************************
欢迎使用CSDN论坛阅读器 : CSDN Reader(附全部源代码)
http://www.cnblogs.com/feiyun0112/archive/2006/09/20/509783.html
string[] s ={ "sadf", "r43io", "gerio", "239", "reag" };
int i;
for (i = 0; i < s.Length; ++i)
if (s[i].Equals(str))
break;
再判断i的边界就知道它的上一位和下一位了