js 调用函数时，弹出提示框为 [object Object]

Question

functionjs

Answer 1

异步执行的是返回不了数据的 只能在success里面处理
你可以传调用一个回调函数来处理
 
  function GetMusicsLength(callback) {
       
            //返回 值
            return $.ajax({
                type: "post",
                cache: false,
                contentType: "application/json",
                url: "@Url.Action("GetMusicsLength", "Shared")",
                data: null,
                dataType: "json",                success: function (result) {
                    
                   //获取返回的值，并赋值给 number
                    number = result.toString();
                  callback(number )
                   //返回 number
                    //return number;                },
                error: function (a, b, c) {
                    alert(c);
                }
            });        }
 function fun1(para){
   alert(para)
}
GetMusicsLength(fun1);如果非要返回的话，可以试试调用ajax的时候添加属性： async：false 也就是不采用异步的方式请求

Answer 2

   function aaa() {           //调用 GetMusicsLength() ，并弹出返回值
//这里只是调用弹出或其它操作就在success里面写好了
          GetMusicsLength();        }        //获取文件个数
    function GetMusicsLength() {
       
            //返回 值
            return $.ajax({
                type: "post",
                cache: false,
                contentType: "application/json",
                url: "@Url.Action("GetMusicsLength", "Shared")",
                data: null,
                dataType: "json",                success: function (result) {
                    
                   //获取返回的值，并赋值给 number
                    number = result.toString();                   //返回 number
                    alert(number);                },
                error: function (a, b, c) {
                    alert(c);
                }
            });        }

Answer 3

在你的$.ajax 中  加上 async:false,
$.ajax({
     async: false,
     type: "post",
    .................
});