Asp.NEt mvc，用jquery+ajax从一个view里获取文本框的值，怎么在另一个View中显示获取的值

Question

asp.netjqueryajaxmvcjson

Answer 1

当做参数请求那个view，view里写一个获取参数的controller

Answer 2

在请求时带上取到的值作为参数，ajax和服务器交互时把参数传过去，controller接到参数放到viewbag或viewdata里面。在第二个view获取便可。

Answer 3

还是本人来结贴吧。
两种方法：
第一种：采用session存值传递到另一个ResultAction
代码如下： public ActionResult Hotel_search(string passport, string country, string city, string location, string enterTime, string leaveTime, string oneInput, string bigInput, string twoInput, string threeInput, string fourInput, string hotelName, string hotelWriteName)
        {
            Session["passport"] = passport;
            //Session["country"] = country;
            //Session["city"] = city;
            //Session["location"] = location;
            //Session["enterTime"] = enterTime;
            //Session["leaveTime"] = leaveTime;
            //Session["oneInput"] = oneInput;
            //Session["bigInput"] = bigInput;
            //Session["twoInput"] = twoInput;
            //Session["threeInput"] = threeInput;
            //Session["fourInput"] = fourInput;
            //Session["hotelName"] = hotelName;
            //Session["hotelWriteName"] = hotelWriteName;
            
            return Redirect("Order_condition");
       
        }
在另一个Action里代码如下：
  public ActionResult Order_condition(string passport, string country, string city, string location, string enterTime, string leaveTime, string oneInput, string bigInput, string twoInput, string threeInput, string fourInput)
        {
            ViewData["passport"] = Session["passport"].ToString();
            ViewData["country"] =Session["country"].ToString();
            ViewData["city"] = Session["city"].ToString();
            ViewData["location"] = Session["location"].ToString();
            ViewData["enterTime"] = Session["enterTime"].ToString();
            ViewData["leaveTime"] = Session["leaveTime"].ToString();
            ViewData["oneInput"] = Session["oneInput"].ToString();
            ViewData["bigInput"] = Session["bigInput"].ToString();
            ViewData["twoInput"] = Session["twoInput"].ToString();
            ViewData["threeInput"] = Session["threeInput"].ToString();
            ViewData["fourInput"] = Session["fourInput"].ToString();
            return View();
        }

Answer 4

第二个方法，直接在Hotel_search.js上的代码上改：
$(function () {
    $("#btn_search_Hotel_search").click(function () {
        toAction("Order_condition", "Customer", "passport=" + $("#txt_passport_Hotel_search").val() +
            "&country=" + $("#txt_country_Hotel_search").val() +
            "&city=" + $("#txt_city_Hotel_search").val() +
            "&location=" + $("#txt_location_Hotel_search").val() +
            "&enterTime=" + $("#txt_enter_time_Hotel_search").val() +
            "&leaveTime=" + $("#txt_leave_time_Hotel_search").val() +
            "&oneInput=" + $("#txt_one_input_Hotel_search").val() +
            "&bigInput=" + $("#txt_big_input_Hotel_search").val() +
            "&twoInput=" + $("#txt_two_input_Hotel_search").val() +
            "&threeInput=" + $("#txt_three_input_Hotel_search").val() +
            "&fourInput=" + $("#txt_four_input_Hotel_search").val() +
            "&hotelName=" + $("#txt_hotel_name_Hotel_search").val() +
            "&hotelWriteName=" + $("#txt_hotelName_write_Hotel_search").val());    });    function getData4Post(actionName, controllerName, paramData) {        var actionUrl = getActionUrl(actionName, controllerName);        try {            $.ajax({
                type: "POST",
                url: actionUrl,
                data: paramData,
                success: function (data) {
                    //alert(data.Passport + " " + data.Country + " " + data.City);
                    toAction("Order_condition", "Customer");
                }
            });
        } catch (e) {
            alert(e);
        }
    };
});
然后直接在Order_condition上显示：
   public ActionResult Order_condition(int passport, string country, string city, string location, DateTime enterTime, DateTime leaveTime, int oneInput, int bigInput, int twoInput, int threeInput, int fourInput)
        {
            ViewData["passport"] = passport;
            ViewData["country"] = country;
            ViewData["city"] = city;
            ViewData["location"] = location;
            ViewData["enterTime"] = enterTime;
            ViewData["leaveTime"] = leaveTime;
            ViewData["oneInput"] = oneInput;
            ViewData["bigInput"] = bigInput;
            ViewData["twoInput"] = twoInput;
            ViewData["threeInput"] = threeInput;
            ViewData["fourInput"] = fourInput;
            return View();
        }
这两种都能把参数给到View所属的ActionResult里，然后再传到相对应的页面，直接用ViewData[" "]显示

Answer 5

6楼的，我是初学者，用Session的方法还是自己从网上查找的。至于你说的直接ViewData，你可以自己代码实现一下看可不可以。