1. make sure you have
<form runat=server enctype="multipart/form-data">2.
for(int i = 0;i < Request.Files.Count; i++)
{
HttpPostedFile PostedFile = Request.Files[i];
////
}see
传(upload)文件的codebehind代码
http://www.71it.com/TecArticle/viewArticleDetail.asp?Articleid=761
<form runat=server enctype="multipart/form-data">2.
for(int i = 0;i < Request.Files.Count; i++)
{
HttpPostedFile PostedFile = Request.Files[i];
////
}see
传(upload)文件的codebehind代码
http://www.71it.com/TecArticle/viewArticleDetail.asp?Articleid=761
解决方案 »
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