急，Request.Form["inputid"].ToString()取不到值

Request.Form["txtChgPassword"].ToString()

解决方案 »

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我是这样写的呀
Request.Form["txtChgPassword"].ToString();
是不是因为INPUT的type是password的原因
那我简单一点，效果是一样的：
private void btnSaveAdd_Click(object sender, System.EventArgs e)
{
Response.Write(Request.Form["txtChgPassword"].ToString());
}<INPUT id="txtChgRePassword" type="password" value="****">
<asp:button id="btnSaveAdd" runat="server" Text="Save&Add"></asp:button>
Response.Write(Request.Form["txtChgPassword"].ToString());
我现在没有VS.NET,所以不能帮你调试.那你试试在Page_Load中写
Response.Write(Request.Form["txtChgPassword"].ToString());
看有没有问题;
if(Request.Form["txtChgPassword"]!=null )
{
  Response.Write(Request.Form["txtChgPassword"].ToString());
}
try!
<INPUT id="txtChgRePassword" type="password" value="****">
<asp:button id="btnSaveAdd" runat="server" Text="Save&Add"></asp:button>是否有放到form当中
表单Form的Method设置为Post并设置action试一下!
<form method="post" runat=server
这个问题可能是你的 webConfig 文件里
<globalization
            requestEncoding="utf-8"            //这两个设置必需一样
            responseEncoding="utf-8"
/>
这两个选项跟.aspx里的字符集设置不一样导致取不到回传的值
在.aspx文件中
<%@ Page Language="C#" ResponseEncoding="xxxxx" %>是否一致,你看看
问题得意解决,代码如下：你的错误可能就是<input 标签没有runat="server"<%@ Page Language="C#"%>
<html>
<head>
<title> New Document </title>
<script Language="c#" runat="server">
  private void btnSaveAdd_Click(object sender, System.EventArgs e)
  {
    if(txtChgRePassword.Value!=null )
    {
      lbl.Text=txtChgRePassword.Value;
}
else
{
   lbl.Text="ERROR";
      btnSaveAdd.Visible=false;
}
}</script>
</head>
<body>
<form runat="server">
<asp:label id="lbl" runat="server"/><br><br>
<INPUT id="txtChgRePassword" type="password" value="How are you!" runat="server"/>
<asp:button id="btnSaveAdd" runat="server" Text="Save&Add" onClick="btnSaveAdd_Click"></asp:button>
</form>
</body>
</html>或是
<%@ Page Language="C#"%>
<html>
<head>
<title> New Document </title>
<script Language="c#" runat="server">
  private void btnSaveAdd_Click(object sender, System.EventArgs e)
  {
    if(txtChgRePassword.Value!=null )
    {
      lbl.Text=txtChgRePassword.Value;
}
else
{
   lbl.Text="ERROR";
      btnSaveAdd.Visible=false;
}
}</script>
</head>
<body>
<form runat="server">
<asp:label id="lbl" runat="server"/><br><br>
<INPUT id="txtChgRePassword" type="password" value="How are you!" runat="server"/>
<asp:button id="btnSaveAdd" runat="server" Text="Save&Add" onClick="btnSaveAdd_Click"></asp:button>
</form>
</body>
</html>或是下面的，不过还是用上面的好，因为ASP.NET新的优秀的特性就是减少了用Request.
<%@ Page Language="C#"%>
<html>
<head>
<title> New Document </title>
<script Language="c#" runat="server">
  private void btnSaveAdd_Click(object sender, System.EventArgs e)
  {
    if(Request.Form["txtChgRePassword"]!=null )
    {
      lbl.Text=Request.Form["txtChgRePassword"].ToString();
}
else
{
   lbl.Text="ERROR";
      btnSaveAdd.Visible=false;
}
}</script>
</head>
<body>
<form runat="server">
<asp:label id="lbl" runat="server"/><br><br>
<INPUT id="txtChgRePassword" type="password" value="How are you!" runat="server"/>
<asp:button id="btnSaveAdd" runat="server" Text="Save&Add" onClick="btnSaveAdd_Click"></asp:button>
</form>
</body>
</html>
如果INPUT是runat="server"，它的value="How are you!"就不会在初试化页面的时候出现
andyy(枫叶)还有别的办法吗
在page_load事件中
可以給他賦予直
if(!Page.IsPostBack)
{
txtChgRePassword.Text = "How are you";
}
yehanyu，在后台能这样写吗：txtChgRePassword.Text
to:win1357(shanking)
当然可以：）