老话重提!求使用TreeView的代码,急急

Question

我也想要,最好是动态的,能从数据库里提取的,我看不容易

Answer 1

Dbconnection obj = new Dbconnection(myConst.ConnString);
string sql = "select * from people where teacher='博士生导师'";
SqlDataReader rs = obj.executeQuery(sql);
while(rs.Read())
{
creatNode(rs["realname"].ToString(),rs["id"].ToString(),rs["id"].ToString(),getNode("博士生导师",people.Nodes));
sql="select * from people where (degree='博士' or degree='博士后') and follow=" + rs["id"].ToString();
SqlDataReader rs1 = objDoctor.executeQuery(sql);
if(rs1.Read())
{
creatNodeNoUrl("博士研究生",rs["id"].ToString() + "doctor",getNode(rs["id"].ToString(),people.Nodes));
creatNode(rs1["realname"].ToString(),rs1["id"].ToString() + "indoctor",rs1["id"].ToString(),getNode(rs["id"].ToString() + "doctor",people.Nodes));
while(rs1.Read())
{
creatNode(rs1["realname"].ToString(),rs1["id"].ToString() + "indoctor",rs1["id"].ToString(),getNode(rs["id"].ToString() + "doctor",people.Nodes));
}
}
rs1.Close();

sql="select * from people where degree='硕士' and follow=" + rs["id"].ToString();
rs1 = objMaster.executeQuery(sql);
if(rs1.Read())
{
creatNodeNoUrl("硕士研究生",rs["id"].ToString() + "master",getNode(rs["id"].ToString(),people.Nodes));
creatNode(rs1["realname"].ToString(),rs1["id"].ToString() + "inmaster",rs1["id"].ToString(),getNode(rs["id"].ToString() + "master",people.Nodes));
while(rs1.Read())
{
creatNode(rs1["realname"].ToString(),rs1["id"].ToString() + "inmaster",rs1["id"].ToString(),getNode(rs["id"].ToString() + "master",people.Nodes));
}
}
rs1.Close();
}
rs.Close();

Answer 2

唉，请看看我的题目!!!!!!!!!!!!!!!

Answer 3

我的意思是当我展开一个结点的时候，其余可以展开的结点折叠起来!

Answer 4

天啦，人都到哪去了，高手啊，救救我!!!!!!!!!!!!!!!!!!!