解决方案 »

  1.   

    2001-03-01 00:00:00.000    2005-03-03 00:00:00.000 work
    2005-07-15 00:00:00.000    2008-11-04 00:00:00.000 work
    2009-04-23 00:00:00.000    9999-12-31 00:00:00.000 work
    2000-02-01 00:00:00.000    2004-06-08 00:00:00.000 study
    2004-05-13 00:00:00.000    2008-10-28 00:00:00.000 study
    2009-05-13 00:00:00.000    9999-12-31 00:00:00.000 study
      

  2.   

    数据已经是在dataset中处理的,与数据库无关.
      

  3.   

    表名:Table_WorkStudy
    员工工号:badge
    开始时间列名:starttime
    结束时间列明:endtime
    类型:type
    思路:select badge,starttime,endtime,type from Table_WorkStudy order by badge,starttime存储在DataSet中的Tables[0]中然后分别判断每个员工的时间