求一正则表达式

Question

求一验证密码的正则表达式，规则如下:
1.密码至少需要8个字符
2.大写字母、小写字母、数字、符号这4类字符中必须有3类

Answer 1

你需要的其实是所谓的密码强度测试
see~http://zuzong.javaeye.com/blog/298140

Answer 2

string pattern="((?<A>[A-Z])|(?<B>[a-z])|(?<C>[1-9])|(?<D>[\\-])){8,}(?(A)|((?(B)|(?!))(?(C)|(?!)))(?(D)|(?!))))(?(B)|((?(A)|(?!))(?(C)|(?!)))(?(D)|(?!))))(?(C)|((?(A)|(?!))(?(B)|(?!)))(?(D)|(?!))))"
(?(D)|((?(A)|(?!))(?(B)|(?!)))(?(C)|(?!))))";

Answer 3

你试试看?string pattern="((?<A>[A-Z])|(?<B>[a-z])|(?<C>[1-9])|(?<D>[\\-])){8,}(?(A)|((?(B)|(?!))(?(C)|(?!)))(?(D)|(?!))))(?(B)|((?(A)|(?!))(?(C)|(?!)))(?(D)|(?!))))(?(C)|((?(A)|(?!))(?(B)|(?!)))(?(D)|(?!))))(?(D)|((?(A)|(?!))(?(B)|(?!)))(?(C)|(?!))))";

Answer 4

运行后报这个错误啊
parsing "((?<A>[A-Z])|(?<B>[a-z])|(?<C>[1-9])|(?<D>[\\-])){8,}(?(A)|((?(B)|(?!))(?(C)|(?!)))(?(D)|(?!))))(?(B)|((?(A)|(?!))(?(C)|(?!)))(?(D)|(?!))))(?(C)|((?(A)|(?!))(?(B)|(?!)))(?(D)|(?!))))(?(D)|((?(A)|(?!))(?(B)|(?!)))(?(C)|(?!))))" - Too many )'s.

Answer 5

JQuery写的代码·
$('#btn_special').click(function(){
                $(this).val('if if pwd[n>=8][type>=3]');
                var text=$('#input_special').val(); 
                var num=0;
                if(text.search(/[A-Z]/)!=-1)
                {
                    num+=1;
                }
                if(text.search(/[0-9]/)!=-1)
                {
                    num+=1;
                }
                if(text.search(/[a-z]/)!=-1)
                {
                    num+=1;
                }
                if(text.search(/[^A-Za-z0-9]/)!=-1)
                {
                    num+=1;
                }
                if(num>=3 && (text.length>=8))
                {
                    vool=true;                                        
                }
                else
                {
                    vool=false;
                }
                $(this).val($(this).val()+':'+vool);
            });
            
        });

Answer 6

string pattern = "((?<A>[A-Z])|(?<B>[a-z])|(?<C>[1-9])|(?<D>[\\-])){8,}(?(A)|((?(B)|(?!))(?(C)|(?!)))(?(D)|(?!)))(?(B)|((?(A)|(?!))(?(C)|(?!)))(?(D)|(?!)))(?(C)|((?(A)|(?!))(?(B)|(?!)))(?(D)|(?!)))(?(D)|((?(A)|(?!))(?(B)|(?!)))(?(C)|(?!)))";我改正了

Answer 7

结贴了，最后参考了mqc507写了
javascript:
        function ValidPassword(strPassword)
        {
            var num=0;
            if(strPassword.search(/[A-Z]/)!=-1)
            {
                num+=1;
            }
            if(strPassword.search(/[0-9]/)!=-1)
            {
                num+=1;
            }
            if(strPassword.search(/[a-z]/)!=-1)
            {
                num+=1;
            }
            if(strPassword.search(/[^A-Za-z0-9]/)!=-1)
            {
                num+=1;
            }
            if(num>=3 && (strPassword.length>=8))
            {
                vool=true;                                        
            }
            else
            {
                vool=false;
            }
            return vool;
        }
C#:
        private bool ValidPassword(string strPassword)
        {
            bool bReturn = false;
            int sumRegex = 0;
            Regex regex1 = new Regex("[A-Z]+");
            Regex regex2 = new Regex("[a-z]+");
            Regex regex3 = new Regex("[0-9]+");
            Regex regex4 = new Regex("[^A-Za-z0-9]");
            if (regex1.IsMatch(strPassword))
                sumRegex += 1;
            if (regex2.IsMatch(strPassword))
                sumRegex += 1;
            if (regex3.IsMatch(strPassword))
                sumRegex += 1;
            if (regex4.IsMatch(strPassword))
                sumRegex += 1;
            if (sumRegex > 2 && strPassword.Length > 7)
                bReturn = true;
            return bReturn;
        }感谢 HDNGO 和 eibo520