用微软ajax控件怎么弹出对话框

Question

用微软ajax控件怎么弹出对话框

Answer 1

ajax太强大，不懂，先占位，学习

Answer 2

        #region Ajax用的警告框
        /// <summary>
        /// Ajax用的警告框
        /// </summary>
        /// <param name="_Msg"></param>
        /// <param name="UP_Name"></param>
        public static void Alert(string _Msg, UpdatePanel UP_Name)
        {
            _Msg = Regex.Replace(_Msg, "\r\n", "\\r\\n", RegexOptions.IgnoreCase);
            System.Web.UI.ScriptManager.RegisterClientScriptBlock(UP_Name, typeof(UpdatePanel), "AjaxMsgBox", "alert('" + _Msg + "');", true);
        }
        #endregion

Answer 3

用ScriptManager.RegisterClientScriptBlock来注册脚本

Answer 4

ScriptManager.RegisterClientScriptBlock(UpdatePanel1, this.GetType(), "click", "alert('asdasd');", true);

Answer 5

ScriptManager.RegisterStartupScript(this.Page, this.Page.GetType(), "", "window.open('url ');", true);