有知道的说下，谢了！

Question

用递归遍历1到100的阶乘

Answer 1

public int jiecheng(int n)//第n个数的阶乘
        {
            if (n == 1)
                return 1;
            else if (n == 2)
                return 2;
            else
                return n * jiecheng(n - 1);        }
        public int sumjiecheng(int n)//n个阶乘的和
        {
            if (n == 1)
                return 1;
            else if (n == 2)
                return 3;            else
                return jiecheng(n) + sumjiecheng(n - 1);
       }sumjiecheng（100）；（计算出1到100以内所有数的阶乘的和）

Answer 2

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;namespace zd3
{
    class Program
    {
        public static double frac(int n)
        {
            if (n == 1)
                return 1;
            else
                return n * frac(n - 1);
        }
        static void Main(string[] args)
        {
            Console.Write(frac(100));
        }
    }
}

Answer 3

http://wenku.baidu.com/view/f3d80535eefdc8d376ee32f8.html