linq to xml问题

Question

例如xml为<company>
   <onecompany>
      <name>csdn</name>
      <info>csdninfo</info>
   </onecompany>
   <twocompany></twocompany>
</company>用linq to xml要怎么取得onecompany下的所有子节点呢？

Answer 1

<company>
   <onecompany id="company1">
      <name>csdn</name>
      <info>csdninfo</info>
   </onecompany>
   <twocompany id="company2">
   </twocompany>
  ...
</company>问题改下
用linq to xml要怎么取得onecompany下的所有子节点和onecompany的id属性呢？
只用linq to xml 
XMlDocument的我会，不用发了喔！

Answer 2

        var xml = from x in XElement.Load(Server.MapPath("XMLFile.xml")).Descendants("onecompany")
                  select new
                  {
                      id = x.Attribute("id").Value,
                      name=x.Element("name").Value,
                      info = x.Element("info").Value
                  };
        foreach (var x in xml)
        {
            Response.Write(x.id + "==" + x.name + "==" + x.info);
        }