关于异步注册脚本的问题

Question

HTML页
    <asp:ScriptManager ID="ScriptManager1" runat="server">
    </asp:ScriptManager>
    <asp:UpdatePanel ID="UpdatePanel1" runat="server">
        <ContentTemplate>
            <asp:Button ID="Button1" runat="server" Text="Button" onclick="Button1_Click" />
        </ContentTemplate>
    </asp:UpdatePanel>
.cs文件
    protected void Button1_Click(object sender, EventArgs e)
    {
        ScriptManager.RegisterStartupScript(this.UpdatePanel1, this.GetType(), "D", "alert(1)", true);
    }
IE左下角显示 网页有错误. 
并且当点击button按钮时,无法弹出对话框,怎么解决?

Answer 1

ScriptManager.RegisterClientScriptBlock()用这个试试.

Answer 2

ScriptManager.RegisterStartupScript(this, this.GetType(), "edit", "ShowMessage('"+ message +"')", true);
function ShowMessage(message)
{
   alert(message);
}

Answer 3

<Triggers><asp:AsyncPostBackTrigger ControlID="Button1" EventName="Click" /></Triggers> 加 这个试试