跳转页面前的弹出框无法显示?

Question

    if (manage.GetRecordNum(userName.Text, passWord.Text) <= 0)
            {
                RegisterStartupScript("hello", "<script>alert('用户名或密码不正确！')</script>");
                return;
            }
            else
            {
                RegisterStartupScript("hello", "<script>alert('登陆成功！')</script>");
                //Response.Write("<Script Language=JavaScript>alert('登陆成功！');</Script>");                Response.Redirect("OperateTest.aspx");
            }
以上代码的"登陆成功"提示无法显示,该怎么改?????

Answer 1

Response.Write("<script>alert('登陆成功！');window.location.href='aaaa.aspx';</script>");

Answer 2

ClientScript.RegisterClientScriptBlock(GetType(), "", "<script>alert(\'登陆成功！\');setTimeout(function(){location.href='OperateTest.aspx'},1000);  </script>");

Answer 3

Response.Write("<script>alert('登陆成功！');window.location.href='aaaa.aspx';</script>");好东西哦

Answer 4

this.Page.ClientScript.RegisterStartupScript(GetType(), "", "<script>alert('注册成功！');location.href='test.aspx';</script>");

Answer 5

 Page.ClientScript.RegisterStartupScript(this.GetType(), "", "<script>alert('弹框！');location.href='你要跳转的页面'</script>");

Answer 6

RegisterStartupScript("hello", "<script>alert('登陆成功！')</script>");
                //Response.Write("<Script Language=JavaScript>alert('登陆成功！');</Script>");                Response.Redirect("OperateTest.aspx");
这两个不能一起用可以先提示在跳转
ClientScript.RegisterStartupScript(Page.GetType(), "", 
"<script>alert('" + str+ "');
window.location.href ='" + strUrl + "';
</script>");
DEMO
string str="成功";
string strUrl="test.aspx";
ClientScript.RegisterStartupScript(Page.GetType(), "", 
"<script>alert('" + str+ "');
window.location.href ='" + strUrl + "';
</script>");

Answer 7

因为这些代码都是运行在服务器上，还没等把登录提示传输到客户端就执行了Response.Redirect("OperateTest.aspx");进行了页面跳转，所以你看不到提示。
可以改成：Response.Redirect("<script>alert('登录成功。');window.location.href='OperateTest.aspx'</script>");或者
Page.ClientScript.RegisterStartupScript(this.GetType(), "", "<script>alert('弹框！');location.href='你要跳转的页面'</script>");后者用户体验更好