求一简单算法

Question

["200","","100","300","" ,"" ,"200","" ]
当遇到这样的数组时，将2/200且分给它后面的空格，3/300同理，类似与将不是100的数 都平分一下。
["100","100","100","100","100","100","100","100"]

Answer 1

遍历数组   元素/100  等于几就往这个下标位置insert 几个100  

Answer 2

            List<int> list= Enumerable.Repeat(100, 10).ToList();
            list.ForEach(p => Console.WriteLine(p));

Answer 3

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Globalization;
using System.IO;
using System.Text.RegularExpressions;namespace ConsoleApplication2
{
    class Program
    {
        static void Main(string[] args)
        {
            string[] strarray =new string[]{"2","","100","","","","200","","",""};
            List<int> indexs = new List<int>();
            for (int i = 0; i < strarray.Length;i++ )
            {
                if (strarray[i] != "")
                {
                    indexs.Add(i);
                }
            }
            List<int> indexe = new List<int>();
            for (int i = 1; i < indexs.Count; i++)
            {
                indexe.Add(indexs[i]);
            }
            indexe.Add(strarray.Length);
            int size = 0;
            for (int i = 0; i < indexs.Count; i++)
            {
                size = indexe[i] - indexs[i]-1;
                int result = int.Parse(strarray[indexs[i]]) / (size+1);
                for (int j = indexs[i]; j < indexe[i]; j++)
                {
                    strarray[j] = result.ToString();
                }
            }
            foreach (string s in strarray)
            {
                Console.Write(s + "  ");
            }
        }
    }
}
//个人不太懂算法！~。
//1 1 25 25 25 25 50 50 50 50

Answer 4

string[] str = new string[] { "100", "200", "400", "800" };
        int sum = 0;
        foreach (string s in str)
        {
            sum += Convert.ToInt32(s) / 100;
        }
        List<string> lt = new List<string>();
        for (int i = 0; i < sum; i++)
        {
            lt.Add("100");
        }