求一段最简洁的ajax代码

Question

如题，想通过ajax实现异步读取数据库的数据，并显示在前台页面，从数据库读取的数据通过xml作为缓存。代码越简练越好，实现功能就行。谢谢

Answer 1

jQuery(function($) {
    var username = $("#username");
    var pwd = $("#pwd");
    var code = $("#code");
    $("#oalogin").click(function() {
    $.post("Ajax/Help/Ajax_Help.ashx?method=login&date=" + new Date().getTime(), { Action: "post", username: username.val(), pwd: pwd.val(), code: code.val()},
        function(data, textStatus) {
            if (data.result == 'Eok') {
                top.location.href = "index.aspx?a0e4=ee11cbb19052e40b07aac0ca060c23ee";
            }
            else if(data.result == 'Aok') { 
                top.location.href = "index.aspx?a0e4=21232f297a57a5a743894a0e4a801fc3";
            }
            else {
                        if(data.result=="Code")
                        {
                           showMsgErr("RegVerifyCode_info","");
                           pass=false;
                           return false;
                           checkform();
                        }
                        else if(data.result=="UP")
                        {
                          showMsgErr("loginid_info","");
                          showMsgErr("password_info","");
                          pass=false;
                          return false;
                          checkform();
                        }
                        else
                        {
                          checkform();
                        }
            }         }, "json");
    });
});