XmlTextReader 解析XML 怎么Element值啊

Question

 XmlTextReader reader = new XmlTextReader(Server.MapPath("ldz.xml"));
        while (reader.Read())
        {            switch (reader.NodeType)
            {
                    
                case XmlNodeType.Element:
   
                    Response.Write("节点名称：" + reader.LocalName + "value:" + XmlNodeType.Text + "<br>");
                    
                    for (int i = 0; i < reader.AttributeCount; i++)
                    {
                        reader.MoveToAttribute(i);
                        Response.Write("属性：" + reader.Name + "=" + reader.Value + "&nbsp;");
                        Response.Write("<br />");
                    }
                    break;            }
        }
        reader.Close();

Answer 1

参考下
http://msdn.microsoft.com/zh-cn/library/e4w1e57w(VS.80).aspx