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Question

 string Id, MenuName, ApplicationId, Levels;
        public ActionResult EditorInterface(string Id,string MenuName,string ApplicationId,string Levels)
        {            ViewData["Id"] = Id;
            ViewData["MenuName"] = MenuName;
            ViewData["ApplicationId"] = ApplicationId;
            ViewData["Levels"] = Levels;
         
            return View();        }
        [HttpPost]
        public ActionResult Content()
        {
            GridDataContext grid = new GridDataContext();             Id = Request.Form["Id"];
             MenuName = Request.Form["MenuName"];
             ApplicationId = Request.Form["ApplicationId"];
             Levels = Request.Form["Levels"];            return RedirectToAction("EditorInterface", new { Id=Id,MenuName=MenuName,ApplicationId=ApplicationId,Levels=Levels});        }
值我已经传到EditorInterface中了 可是我load弹出EditorInterface的视图时，它都执行两遍EditorInterface方法，第二遍执行时 就又没有值了，所以还是传不上，不知道有什么方法解决没，谢谢了

Answer 1

补充一下我弹出的代码是： function Editor() {
            var id = $("#table1").jqGrid("getGridParam", "selrow");//获取选中行的Id
            var rowData = $("#table1").jqGrid("getRowData", id); //获取选中行的数据
            var EditorConteng = { Id: rowData.Id, MenuName: rowData.MenuName, ApplicationId: rowData.ApplicationId, Levels: rowData.Levels };
            
                $.ajax({                    url: '<%=Url.Content("~/Grid/Content/")%>',
                    type: 'post',
                    dataType: 'json',
                    data: EditorConteng,
                    success: function () {
                    },
                    complete: function () {
                        $("#Editor").html("").load('<%=Url.Content("~/Grid/EditorInterface/")%>');
                        $("#Editor").dialog("open");                    }                });
            
          
                };

Answer 2

dataType:"html", // string
success: function (html) {
  $("#Editor").html("").load(html);
  $("#Editor").dialog("open");
},
complete: function () {                    
}你ajax的时候 返回的就是 你要的视图，不用再一次 去load那个视图了。

Answer 3

没有 试过， 理论应该可以的
$("#Editor").html("").html(html);
 $("#Editor").dialog("open");

Answer 4

好了 谢谢啊 应该是这样的   $.ajax({                    url: '<%=Url.Content("~/Grid/Content/")%>',
                    type: 'post',
                    dataType: 'html',
                    data: EditorConteng,
                    success: function (html) {
                        $("#Editor").html(html);
                        
                    }
                });
                $("#Editor").dialog("open");
                };