<html xmlns="http://www.w3.org/1999/xhtml" >
<head runat="server">
    <title>图片互换</title>
    
    <script language="javascript" type="text/javascript">
    
    function img1_onmouseover(){
    img1.src="2.jpg";
    }
    
    function img1_onmouseout(){
    img1.src="1.jpg";
    }
    
    </script>
    
</head>
<body>
    <form id="form1" runat="server">
    
    <img id =img1 src="App_Data/picture1.jpg"  language="javascript"
    
    onmouseover="return img1_onmouseover()"
    
    onmouseout="return img1_onmouseout()" />
    
    </form>
</body>
</html>picture1.jpg和picture2.jpg放在App_DaTa下请问这个程序有什么错误啊?

解决方案 »

  1.   


    function img1_onmouseover(){ 
        document.getElementById('img1').src="2.jpg"; 
        }
    function img1_onmouseout(){ 
        document.getElementById('img1').src="1.jpg"; 
        } 
      

  2.   


    <html xmlns="http://www.w3.org/1999/xhtml" > 
    <head id="Head1" runat="server"> 
        <title>图片互换 </title> 
        
        <script language="javascript" type="text/javascript"> 
        
        function img1_onmouseover(){ 
        document.getElementById("img1").src="2.jpg"; 
        } 
        
        function img1_onmouseout(){ 
        document.getElementById("img1")="1.jpg"; 
        } 
        
        </script> 
        
    </head> 
    <body> 
        <form id="form1" runat="server"> 
        
        <img id ="img1" src="App_Data/picture1.jpg"  onmouseover="return img1_onmouseover()"  onmouseout="return img1_onmouseout()" /> 
        
        </form> 
    </body> 
    </html> 
      

  3.   

    路径
    img1.src="App_Data/2.jpg";