<html xmlns="http://www.w3.org/1999/xhtml" >
<head runat="server">
<title>图片互换</title>
<script language="javascript" type="text/javascript">
function img1_onmouseover(){
img1.src="2.jpg";
}
function img1_onmouseout(){
img1.src="1.jpg";
}
</script>
</head>
<body>
<form id="form1" runat="server">
<img id =img1 src="App_Data/picture1.jpg" language="javascript"
onmouseover="return img1_onmouseover()"
onmouseout="return img1_onmouseout()" />
</form>
</body>
</html>picture1.jpg和picture2.jpg放在App_DaTa下请问这个程序有什么错误啊?
<head runat="server">
<title>图片互换</title>
<script language="javascript" type="text/javascript">
function img1_onmouseover(){
img1.src="2.jpg";
}
function img1_onmouseout(){
img1.src="1.jpg";
}
</script>
</head>
<body>
<form id="form1" runat="server">
<img id =img1 src="App_Data/picture1.jpg" language="javascript"
onmouseover="return img1_onmouseover()"
onmouseout="return img1_onmouseout()" />
</form>
</body>
</html>picture1.jpg和picture2.jpg放在App_DaTa下请问这个程序有什么错误啊?
function img1_onmouseover(){
document.getElementById('img1').src="2.jpg";
}
function img1_onmouseout(){
document.getElementById('img1').src="1.jpg";
}
<html xmlns="http://www.w3.org/1999/xhtml" >
<head id="Head1" runat="server">
<title>图片互换 </title>
<script language="javascript" type="text/javascript">
function img1_onmouseover(){
document.getElementById("img1").src="2.jpg";
}
function img1_onmouseout(){
document.getElementById("img1")="1.jpg";
}
</script>
</head>
<body>
<form id="form1" runat="server">
<img id ="img1" src="App_Data/picture1.jpg" onmouseover="return img1_onmouseover()" onmouseout="return img1_onmouseout()" />
</form>
</body>
</html>
img1.src="App_Data/2.jpg";