怎么取出长度为4的项急急

Question

string str=" 00,0000,000001,000002,000003,0001,0002,000201,000202,000203,0003,0004,0005,0006,0007,0008,0009,0010,0011"
怎么取出长度为4的项

Answer 1

string.Split 根据”，“来截取成数组
循环数组
string.Contains 来检测是否包含4

Answer 2

string str=" 00,0000,000001,000002,000003,0001,0002,000201,000202,000203,0003,0004,0005,0006,0007,0008,0009,0010,0011";string[] ss=str.Split(',');for(int i=0;i<ss.Length;i++)
{
   if(ss[i].Length==4)
   Console.WriteLine(ss[i]);
 
}

Answer 3

var quer = from p in str.Split(',')
                       where p.Length == 4
                       select p;

Answer 4

var quer = from p in str.Split(',')
                       where p.Length == 4
                       select p;

Answer 5

LINQ            string source = @"00,0000,000001,000002,000003,0001,0002,000201,000202,000203,0003,0004,0005,0006,0007,0008,0009,0010,0011";
            string[] ss = source.Split(',');
            var vs = from s in ss where s.Length == 4 select s;
            foreach (var v in vs)
            {
                MessageBox.Show(v.ToString());
            }

Answer 6

        string str = " 00,0000,000001,000002,000003,0001,0002,000201,000202,000203,0003,0004,0005,0006,0007,0008,0009,0010";
        string[] sxx = str.Split(',');
        foreach (string xjj in sxx)
        {
            if (xjj.Length == 4)
            {
                Response.Write(xjj+"<br />");
            }
        }
这样写就好了！

Answer 7

string str = "00,0000,000001,000002,000003,0001,0002,000201,000202,000203,0003,0004,0005,0006,0007,0008,0009,0010,0011";
            var quer = from p in str.Split(',')
                       where p.Length == 4
                       select p;
string[] str1 = quer.ToArray();

Answer 8

或使用正则，可能不完善            string source = @"00,0000,000001,000002,000003,0001,0002,000201,000202,000203,0003,0004,0005,0006,0007,0008,0009,0010,0011";
            Regex reg = new Regex(@"(?<=,)\d{4}(?=,)");
            MatchCollection mc = reg.Matches(source);
            foreach (Match m in mc)
            {
                MessageBox.Show(m.Value);
            }