C#二维数组问题。

Question

                        int[][] DayNumbers = new int[][] { };
                        for (int Number = 1; Number < MonthDays; Number++)
                        {
                            for (int i = 0; i < 6; i++)
                                for (int j = 0; j < 7; j++)
                                {
                                    DayNumbers[i][j] = Number;//IndexOutOfRangException索引超出了数组界限。
                                }
                            DayNumbers[0][0] = 0;
                            DayNumbers[0][1] = 0;
                            DayNumbers[0][2] = 0;
                        }
                        return DayNumbers;

Answer 1

int[][] DayNumbers = new int[][] { };你的数组是0维0列的啊，所以赋值出错啊。

Answer 2

int[][] DayNumbers = new int[][] { };数组定义不对吧!!长度为0

Answer 3

我要是写成：int[][] DayNumbers = new int[6][7];//还没编译，IDE就提示：无效的秩说明符: 应为“,”或“]”int[][] DayNumbers = new int[][7];//还没编译，IDE就提示：无效的秩说明符: 应为“,”或“]”就只有int[][] DayNumbers = new int[][] { };编译通过。运行时出//IndexOutOfRangException索引超出了数组界限。的错

Answer 4

首先你这个不是二维数组，而是锯齿形数组，其次，你没有为数组初始化，参考:                        int[][] DayNumbers = new int[6][] { };
                        for (int Number = 1; Number < MonthDays; Number++)
                        {
                            for (int i = 0; i < 6; i++)
                            {
                                DayNumbers[i] = new int[7];
                                for (int j = 0; j < 7; j++)
                                {
                                    DayNumbers[i][j] = Number;
                                }
                            }
                        }
                        return DayNumbers;

Answer 5

int[][] DayNumbers = new int[6][];
                        for (int Number = 1; Number < MonthDays; Number++)
                        {
                            for (int i = 0; i < 6; i++)
                                for (int j = 0; j < 7; j++)
                                {
                                    DayNumbers[i][j] = Number;//IndexOutOfRangException索引超出了数组界限。
                                }
                            DayNumbers[0][0] = 0;
                            DayNumbers[0][1] = 0;
                            DayNumbers[0][2] = 0;
                        }
                        return DayNumbers;

Answer 6

int[,] DayNumbers = new int[6,7]; //这个才是多维数组
                        for (int Number = 1; Number < MonthDays; Number++)
                        {
                            for (int i = 0; i < 6; i++)
                                for (int j = 0; j < 7; j++)
                                {
                                    DayNumbers[i,j] = Number;//注意写法[i,j]
                                }
                            DayNumbers[0,0] = 0;
                            DayNumbers[0,1] = 0;
                            DayNumbers[0,2] = 0;
                        }
                        return DayNumbers;

Answer 7

http://www.mapgou.cn/blogs/dotnet/93.html二维数组与非整齐数组要分清楚哦

Answer 8

//..........
int[,] = new int[6,7];
i[0,0] = 0;
i[0,1] = 1;
i[1,0] = 2;
i[1,1] = 3;
//...........

Answer 9

up，LZ基础知识不扎实。C#中多为数组定义的格式和C/C++稍微有点儿差别。

Answer 10

锯齿数组的第一维必须在申请时指定，int[][] DayNumbers=new int[6][] { };
然后第二维可以在使用时再指定。
另外如果数组存放统一类型的数据，多维数组可以这样定义 int[,] arr = new int[,];