static string GetRandomNumber80(int seed)
{
Random random = new Random(seed);
string[] strs = new string[80];
for (int i = 0; i < strs.Length; i++)
{
strs[i] = random.Next(200,1001).ToString();
}
return string.Join(",", strs.ToArray());
} 这个代码生成的是有重复的伪随机函数,如果不要重复的怎么改呢?
{
Random random = new Random(seed);
string[] strs = new string[80];
for (int i = 0; i < strs.Length; i++)
{
strs[i] = random.Next(200,1001).ToString();
}
return string.Join(",", strs.ToArray());
} 这个代码生成的是有重复的伪随机函数,如果不要重复的怎么改呢?
int iSeed=10;
Random ro = new Random(10);
long tick = DateTime.Now.Ticks;
Random ran = new Random((int)(tick & 0xffffffffL) | (int) (tick >> 32));
Random ran = new Random((int)(tick & 0xffffffffL) | (int) (tick >> 32)); 这个就行了……
static string GetRandomNumber80(int seed)
{
List<int> list = new List<int>();
Random random = new Random(seed);
while(list.Count < 80)
{
int i = random.Next(200,1001);
if(!list.Contains(i))
list.Add(i);
}
return string.Join(",", list.ConvertAll<string>(Convert.ToString).ToArray());
}
{
int j;
List<int> lst=new List<int>();
Random r=new Random();
for(j=0;j<Number;j++)
{
int i=r.Next(minNum,maxNum);
int num=0;
for(int k=0;k<j;k++)
{
if(lst[k]==i)
{
num=num+1;
}
}
if(num==0 )
{
lst[j]=i;
}
else
{
j=j-1;
}
}
return lst;
}