用C#如何实现QQ的窗口抖动!

Question

用C#如何实现QQ的窗口抖动!.会的回答下,谢谢!!

Answer 1

改变窗口位置就好的啊
用个while循环就可以了啊

Answer 2

改变窗口位置
可看看myqq
参考

Answer 3

参考下:using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
using System.Runtime.InteropServices;
namespace 活动窗体震动
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }        internal struct RECT 
        {
            public int left;
            public int top;
            public int right;
            public int bottom;
        }        [DllImport("user32.dll", ExactSpelling = true, SetLastError = true)]
        internal static extern IntPtr GetForegroundWindow();        [DllImport("user32.dll", CharSet = CharSet.Auto, CallingConvention = CallingConvention.StdCall, ExactSpelling = true, SetLastError = true)]
        internal static extern bool GetWindowRect(IntPtr hWnd, ref RECT rect);
        
        [DllImport("user32.dll", CharSet = CharSet.Auto, CallingConvention = CallingConvention.StdCall, ExactSpelling = true, SetLastError = true)]
        internal static extern void MoveWindow(IntPtr hwnd,int X,int Y,int nWidth,int nHeight,bool bRepaint);
        IntPtr id;
        RECT Rect = new RECT();
        private void timer1_Tick(object sender, EventArgs e)
        {          
            id = GetForegroundWindow();
              Random myRandom = new Random();
            GetWindowRect(id, ref Rect);
           MoveWindow(id, myRandom.Next(1024), myRandom.Next(768), Rect.right-Rect.left, Rect.bottom-Rect.top, true);
        }
        
    }
}

Answer 4

 }        //窗体抖动
        private void button2_Click(object sender, EventArgs e)
        {
          
            int recordx = this.Left;
            int recordy = this.Top;
            Random random = new Random();
            for (int i = 0; i < 30; i++)
            {
                int x = random.Next(10);
                int y = random.Next(10);
                if (x % 2 == 0)
                {
                    this.Left = this.Left + x;
                }
                else
                {
                    this.Left = this.Left - x;
                }
                if (y % 2 == 0)
                {
                    this.Top = this.Top + y;
                }
                else
                {
                    this.Top = this.Top - y;
                }            }
            this.Left = recordx;
            this.Top = recordy;
                    }通过控制for 循环,x,y的随机种子,还有this.Left = recordx;
            this.Top = recordy; 是否在循环里,可以达到不同的效果