模拟抛硬币过程

Question

编写一个应用程序模拟抛硬币的过程。要求：用户输入1时，开始抛硬币，并显示结果，
输入2时，显示硬币每面出现的次数，以及出现的概率，
输入0时，结束应用程序，
要用C#

Answer 1

            Random ran = new Random();
            
            ran.Next(0, 1);

Answer 2

 class Program
        {
            int neg = 0, pos = 0;
            int turn = 0;
            public Program(int turn)
            {
                this.turn = turn;
            }            public void start()
            {
                Random rand = new Random();
                for (int i = 0; i < turn; i++)
                {
                    result(rand.Next(0, 1));
                }
            }
            public void result(int i)
            {
                if (i == 0)                    neg++;//正面的次数
                else if (i == 1)
                    pos++;//反面的次数
                else
                    Console.WriteLine("error!");
            }
            public void print()
            {
                Console.WriteLine("抛硬币的次数：{0}", turn);
                Console.WriteLine("正面出现的次数：{0}", neg);
                Console.WriteLine("正面出现的概率：{0}%", neg / turn * 100);
                Console.WriteLine("反面出现的次数：{0}", pos);
                Console.WriteLine("反面出现的概率：{0}%", pos / turn * 100);
            }            public void process()
            {
                int j;
                Console.WriteLine("请输入1开始抛硬币");
                j = Convert.ToInt32(Console.ReadLine());
                if (j == 1)
                {
                    Console.WriteLine("请输入抛硬币的次数：{0}");
                    turn = Convert.ToInt32(Console.ReadLine());
                    start();
                    Console.WriteLine("输入数字2显示抛掷的结果：");
                    j = Convert.ToInt32(Console.ReadLine());
                }
                if (j == 2)                    print();
                    
            }
            static void Main(string[] args)
            {
                Program play = new Program(0);
                play.process();
                Console.Read();            }
        }

Answer 3

谢谢上面各位楼主的帮忙，我的问题才得以解决，对6楼的答案，我调试了一下，做一下修改就完美啦！  再次感谢！
class Program
    {
        int neg = 0, pos = 0;
        int turn = 0;
       
        public Program(int turn)
        {
            this.turn = turn;
        }        public void start()
        {
            Random rand = new Random();
            for (int i = 0; i < turn; i++)
            {
                result(rand.Next(0, 2));
            }
        }
        public void result(int i)
        {
            if (i == 0)                neg++;//正面的次数 
            else if (i == 1)
                pos++;//反面的次数 
            else
                Console.WriteLine("error!");
        }
        public void print()
        {
            Console.WriteLine("抛硬币的次数：{0}", turn);
            Console.WriteLine("正面出现的次数：{0}", neg);
            Console.WriteLine("正面出现的概率：{0}%", neg * 100 / turn);
            Console.WriteLine("反面出现的次数：{0}", pos);
            Console.WriteLine("反面出现的概率：{0}%", pos * 100 / turn );
        }        public void process()
        {
            int j;
            Console.WriteLine("请输入1开始抛硬币");
            j = Convert.ToInt32(Console.ReadLine());
            if (j == 1)
            {
                Console.WriteLine("请输入抛硬币的次数：");
                turn = Convert.ToInt32(Console.ReadLine());
                start();
                Console.WriteLine("输入数字2显示抛掷的结果：");
                j = Convert.ToInt32(Console.ReadLine());
            }
            if (j == 2)                print();        }
        static void Main(string[] args)
        {
            Program play = new Program(0);
            play.process();
            Console.Read();        }
    }