有如下XML文件:
<students>
<team id=1>
<name>张三</name>
<name>李四</name>
<name>王五</name>
<team>
<team id=2>
<name>周杰</name>
<name>曹操</name>
<team>
</students>如果这个xml文件直接给DataSet,并显示在DataGridView上,会显示错误...那么如何才能实现对XML文件的修改,使的其变成如下形式:
<students>
<team id=1>
<name>张三 李四 王五</name>
<team>
<team id=2>
<name>周杰 曹操</name>
<team>
</students>最好是来C#,谢谢大家咯... :)
<students>
<team id=1>
<name>张三</name>
<name>李四</name>
<name>王五</name>
<team>
<team id=2>
<name>周杰</name>
<name>曹操</name>
<team>
</students>如果这个xml文件直接给DataSet,并显示在DataGridView上,会显示错误...那么如何才能实现对XML文件的修改,使的其变成如下形式:
<students>
<team id=1>
<name>张三 李四 王五</name>
<team>
<team id=2>
<name>周杰 曹操</name>
<team>
</students>最好是来C#,谢谢大家咯... :)
doc.Load(@"D:\TestData\1.xml");
XmlNodeList nodelist = doc.DocumentElement.GetElementsByTagName("team");
StringBuilder build = new StringBuilder();
int j = 0;
foreach (XmlNode node in nodelist)
{ for (; j < node.ChildNodes.Count; )
{
if (node.ChildNodes[j].Name == "name")
{
build.Append(node.ChildNodes[j].InnerText);
build.Append(" ");
node.RemoveChild(node.ChildNodes[j]);
j = 0;
}
else
{
j++;
}
}
XmlElement el = doc.CreateElement("name");
el.InnerText = build.ToString();
node.AppendChild(el);
}
doc.Save(@"D:\TestData\1.xml");
XmlDocument doc = new XmlDocument();
doc.Load(@"D:\TestData\1.xml");
XmlNodeList nodelist = doc.DocumentElement.GetElementsByTagName("team");
StringBuilder build = new StringBuilder();
int j = 0;
foreach (XmlNode node in nodelist)
{ for (; j < node.ChildNodes.Count; )
{
if (node.ChildNodes[j].Name == "name")
{
build.Append(node.ChildNodes[j].InnerText);
build.Append(" ");
node.RemoveChild(node.ChildNodes[j]);
j = 0;
}
else
{
j++;
}
}
XmlElement el = doc.CreateElement("name");
el.InnerText = build.ToString();
node.AppendChild(el);
build.Remove(0,build.Length);//加这个
}
doc.Save(@"D:\TestData\1.xml");