在线等候高手解决

Question

using System;
using System.Collections.Generic;
using System.Text;namespace ExConsol2
{
    class Group
    {
        public const int MaxNum = 8;
        private string[] member1;
        //索引器
        public string this[int idx]
        {
            get
            {
                return member1[idx];
            }
            set
            {
                member1[idx] = value;
            }
        }        //--------------------------------------
        private string[] member2;
        //索引器
        //public string this[int idx]
        //{
        //    get
        //    {
        //        return member2[idx];
        //    }
        //    set
        //    {
        //        member2[idx] = value;
        //    }
        //}
        public Group()
        {
            member1 = new string[MaxNum];
            member2 = new string[MaxNum];
        }
        //}
        //=========================================
        //class Program
        //{
        public static void Main(string[] args)
        {
            Group group = new Group();
            //赋值
            group[0] = "张三";
            group[1] = "李四";
            group[2] = "张三";
            group[3] = "李四";
            group[4] = "张三";
            group[5] = "李四";
            group[6] = "张三";
            group[7] = "李四";            for(int i=0;i<Group.MaxNum;i++)
                Console.WriteLine(group[i]);//取值
        }
        //}
    }}
我想在此类中用两个相同类型的两个数组的索引,应该怎么办,如果是一个那么该怎么区分我索引的是哪一个数组??

Answer 1

索引器允许重载，一个类可以有多个索引器。
//索引器 
        public string this[int idx] 
        { 
            get 
            { 
                return member1[idx]; 
            } 
            set 
            { 
                member1[idx] = value; 
            } 
        }         //-------------------------------------- 
        private string[] member2; 
        //索引器 
        //public string this[int idx] 
        //{ 
        //    get 
        //    { 
        //        return member2[idx]; 
        //    } 
        //    set 
        //    { 
        //        member2[idx] = value; 
        //    } 
        //} 
但这么写不构成重载
尝试下面看看
//public string this[string idx] 
        //{ 
        //    get 
        //    { 
        //        return member2[int.Parse(idx)]; 
        //    } 
        //    set 
        //    { 
        //        member2[int.Parse(idx)] = value; 
        //    } 
        //} 
希望对你有用

Answer 2

            private string[] member1;            private string[] member2;            
            
            public string this[int idx]
            {
                get
                {
                    return member1[idx];
                }
                set
                {
                    member1[idx] = value;
                }
            }                        public string this[int idx, int type]
            {
                get
                {
                    switch (type)
                    {
                        case 2:
                            return member2[idx];
                        default:
                            return member1[idx];
                    }
                }
                set
                {
                    switch (type)
                    {
                        case 2:
                            member2[idx] = value;
                            break;
                        default:
                            member1[idx] = value;
                            break;
                    }
                }
            }

Answer 3

谢谢,HASSLE,这个就是所想要的结果