怎么用list列表中的某一列当条件去查询然后显示在listview上

Question

我有两个list列表，都是根据数据库中查出来的list<users>和list<log>，其中log中usersID和users中的ID关联，我想把log显示在listview上，把usersID那一列换成users中的name，怎么弄

Answer 1

用linq轻松解决
List<Users> list1,
List<Log> list2
var result = from r1 in list1
             from r2 in list2
             where r1.UserID == r2.Id
             select new { Id = r1.UserID, Name = r1.UserName, Content = r2.Content };new 的新类里面放你想放的东西，
类似视图，
再直接绑定就行了

Answer 2

        private void button1_Click(object sender, EventArgs e)
        {
            ColumnHeader name = new ColumnHeader();
            name.Text = "name";
            name.Width = 100;
            ColumnHeader log = new ColumnHeader();
            log.Text = "log";
            log.Width = 200;
            
            listView1.Columns.AddRange(new ColumnHeader[] { name, log });
            listView1.View = View.Details;           List<A> listA = new List<A>{
               new A( "1","LogAAAAAAAA"),
               new A( "2","Log2AAAAAAAA")
           };
           List<B> listB = new List<B>{new B("1","NmaeBBBB"),
           new B("2","NmaeCC")};
            var itemb = new List<B>();            listA.ForEach((item) =>
            {
                foreach (var listb in listB)
                {
                    if (item.userid == listb.userid)
                    {                        ListViewItem lvi1 = new ListViewItem(new string[] { listb.username, item.log});
                        listView1.Items.Add(lvi1);
                    }
                }
            });
        }
        class A
        {
            public A(string userid,string log)
            {
                this.userid = userid;
                this.log = log;
            }
            public string userid
            {
                get;
                set;
            }            public string log
            {
                get;
                set;
            }        }        class B
        {
            public  B(string userid,string username)
            {
                this.userid = userid;
                this.username = username;            }
            public string userid
            {
                get;
                set;
            }
            public string username
            {
                get;
                set;
            }
        }

Answer 3

"NmaeBBBB"  "LogAAAAAAAA"
"NmaeCC"    "Log2AAAAAAAA"