求：算法

Question

List<string> one = new List<string>{"0101","0202",”0303","0404"};
List<string> target = new List<string>{"0505","0606","0707","0808","0909",
   "1515","1616","1717","1818","1919",
   "2525","2626","2727","2828","2929",
   "3535","3636","3737","3838","3939"};想实现的效果0505~0909与0101拼接
1515~1919与0202拼接
2525~2929与0303拼接
3535~3939与0404拼接01010505，01010606，01010707，01010808，01010909
02021515，02021616，02021717，02021818，02021919
03032525，03032626，03032727，03032828，03032929
....

Answer 1

target = target.Select((a, i) => { return one[i / (target.Count/one.Count)] + a; }).ToList();

Answer 2

你刚才不是问过了= =！！
这个好像又不一样了。int temp = 0;
for (int i = 0; i < one.Count;i++)
{
   for (n=temp;n <= target.Count; n++)
   {
   Console.WriteLine(one[i] + target[n]);
if((n+1)%4==0)
{
temp=n
break;
}
}
}