如何创建Xml?

Question

<Data ID="11">
<DataName ID="1122">
  <DataValue ID="112233">xxxx</DataValue> 
  </DataName>
</Data>如何创建这样的Xml?

Answer 1

http://www.alixixi.com/program/a/2008050727580.shtml

Answer 2

http://kb.cnblogs.com/a/1320636

Answer 3

XmlDocument xmlDoc = new XmlDocument();
XmlElement root = xmlDoc.CreateElement("Data");
root.SetAttribute("ID", "11");
xmlDoc.AppendChild(root);
XmlElement dataName = xmlDoc.CreateElement("DataName");
dataName.SetAttribute("ID", "1122");
root.AppendChild(dataName);
XmlElement dataValue = xmlDoc.CreateElement("DataValue");
dataValue.SetAttribute("ID", "112233");
dataValue.InnerXml = "xxxx";
dataName.AppendChild(dataValue);
xmlDoc.Save(@"c:\test.xml");
执行完毕，到c:\下找test.xml

Answer 4

            XDocument xdoc = new XDocument(new XDeclaration("1.0", "utf-8", "yes"));
            XElement xele = new XElement("Data", new XAttribute("ID", "111"));
            XElement xeleChild = new XElement("DataName", new XAttribute("ID", "222"));
            XElement xeleChild2 = new XElement("DataValue", new XAttribute("ID", "333"),"XXX");
            xeleChild.Add(xeleChild);
            xele.Add(xeleChild);
            xdoc.Add(xele);
            xdoc.Save("xxx.xml");

Answer 5

XmlDocument xmldoc = new XmlDocument();
XmlElement root=xmldoc.CreateElement("Data");
root.SetAttribute("ID","11");
xmldoc.AppendChild(root);
XmlElement childSec=xmldoc.CreateElement("DataName");
childSec.SetAttribute("ID","1122");
root.AppendChild(childSec);
XmlElement childThr=xmldoc.CreateElement("DataValue");
childThr.SetAttribute("ID","112233");
childThr.InnerText="xxxx";
childSec.AppendChild(childThr);

Answer 6

推荐使用xml.linq的命名空间下的那一套xmlapi用起来比较爽
XElement Data=new XElement("Data",new XAttribute("ID",11));
            XElement DataName=new XElement("DataName",new XAttribute("ID",1122));
            XElement DataValue=new XElement("DataValue",new XAttribute("ID",112233),new XText("xxxx"));
            Data.Add(DataName);
            DataName.Add(DataValue);//save
Data.Save("路径");