关于数组出界问题？

Question

  d是个6×6的二维数组，textboxs[n]含6个元素的一维数组，n=6
for (int i = 0; i< 6; i++)
                {
                    for (int j = 0; j < 6; j++)
                    {
                        s1 = d[i, j];
                        p1 = s1.Split(',');
                        if (p1[4] != "0")
                        {
                            
                            textboxs[n].Text = p1[2];
                                                        n++;
                            if (n > 6)
                                continue;
                        }
为什么n会运行到6呢？还有运行到n=6时说出界了呢？

Answer 1

textboxs[n]含6个元素的一维数组，n=6 
不是只有0-5吗？

Answer 2

for (int i = 0; i < 5; i++) 
                { 
                    for (int j = 0; j < 5; j++) 
                    { 
                        s1 = d[i, j]; 
                        p1 = s1.Split(','); 
                        if (p1[4] != "0") 
                        { 
                            
                            textboxs[n].Text = p1[2]; 
                                                        n++; 
                            if (n > 5) 
                                continue; 
                        } 

Answer 3

i<5,j<5的话不是遍历不了了6×6的数组了？

Answer 4

我也不知道呢，我改成if(n==5)，也是错的。。

Answer 5

  if (n > 6) 
                                continue; 
改为break;

Answer 6

应该是continue的原因..你想想..当N>6后..你还让他继续执行    然而continue是作用于if语句中.而不是for语句中.你想想就知道了.当n=6     if (p1[4] != "0") 
                        { 
                            
                            textboxs[6].Text = p1[2]; 
                                                        n++; 
                            if (n > 5) 
                                continue; 
                        } 
   超界了...呵...不知道是不是分析正确哦.

Answer 7

if (n >= 6) 

Answer 8

for (int i = 0; i < 6; i++) 
                { 
                    for (int j = 0; j < 6; j++) 
                    { 
                        s1 = d[i, j]; 
                        p1 = s1.Split(','); 
                        if (p1[4] != "0") 
                        { 
                            
                            textboxs[n].Text = p1[2]; 
                                                        n++; 
                            if (n >= 6) 
                                break; //跳出内层循环
                        } 
                     }
                     if(n >= 6)
                     break;//跳出外层循环
                     }

Answer 9

这样还有问题么？                int n = 0;
                for (int i = 0; i < 6 && n < 6; i++) 
                { 
                    for (int j = 0; j < 6 && n < 6; j++) 
                    { 
                        s1 = d[i, j]; 
                        p1 = s1.Split(','); 
                        if (p1[4] != "0") 
                        {                             
                            textboxs[n++].Text = p1[2];                    
                            } 
                     }
                     }

Answer 10

检查下你的d[i, j]里面的内容，是不是循环重复的，调试下。

Answer 11

textboxs[6]的索引应该是0-5
就是textboxs[0]~textboxs[5]把代码都贴出来看看

Answer 12

我的d[i,j]是不重复的，我检查过了

Answer 13

for (int i = 0; i < 6; i++) 
                { 
                    for (int j = 0; j < 6; j++) 
                    { 
                            if (n > 6) 
                                break; 
                        s1 = d[i, j]; 
                        p1 = s1.Split(','); 
                        if (p1[4] != "0") 
                        { 
                            
                            textboxs[n].Text = p1[2]; 
                                                        n++;                         } 
}

Answer 14

            data = new string[,] {{"stage1,1,step1,95.10,60","stage1,1,step2,94.0,11","stage1,0,step3,0,0","stage1,0,step4,0,0","stage1,0,step5,0,0","stage1,0,step6,0,0"},
                                 {"stage2,35,step1,50.0,15","stage2,35,step2,55.0,15","stage2,35,step3,72.0,30","stage2,35,step4,11,30","stage2,0,step5,0,0","stage2,0,step6,0,0"},
                                 {"stage3,1,step1,72.0,420","stage3,1,step2,4.0,1","stage3,0,step3,0,0","stage3,0,step4,0,0","stage3,0,step5,0,0","stage3,0,step6,0,0"},
                                 {"stage4,2,step1,10,4","stage4,2,step2,0,5","stage4,0,step3,0,0","stage4,0,step4,0,0","stge4,0,step5,0,0","stage4,0,step6,0,0"},
                                 {"stage5,1,step1,10,11","stage5,1,step2,20,52","stage5,1,step3,0,0","stage5,1,step4,0,0","stage5,0,step5,0,0","stage5,0,step6,0,0"},
                                 {"stage6,0,step1,0,0","stage6,0,step2,0,0","stage6,0,step3,0,0","stage6,0,step4,0,0","stage6,0,step5,0,0","stage6,0,step6,0,0"}
                                 };
          stages = new Label[] { stage1, stage2, stage3, stage4, stage5, stage6 };
            cyclebts = new Button[] { cyclebt1, cyclebt2, cyclebt3, cyclebt4, cyclebt5, cyclebt6 };
            temps = new Label[] { temp1, temp2, temp3, temp4, temp5, temp6 };
            times = new Label[] { time1, time2, time3, time4, time5, time6 };
            stepbts = new Button[] { stepbt1, stepbt2, stepbt3, stepbt4, stepbt5, stepbt6 };
   for (int i2 = 0; i2 < 6 &&n<6; i++)
                {
                    for (int j = 0; j < 6 && n < 6; j++)
                    {
                        s1 = data[i2, j];
                        p1 = s1.Split(',');
                        if (p1[4] != "0")//当step的时间不为零
                        {
                            //step[n] = p1[2];
                            stepbts[n].Text = p1[2];
                            temps[n].Text = p1[3];
                            times[n].Text = p1[4];
                            n++;
                          
                        }
其实最好下标都变成I,J之类的，这样我就能再进一步操作了，呵呵

Answer 15

for (int i2 = 0; i2 < 6 &&n <6; i++) 
                { 
                    for (int j = 0; j < 6 && n < 6; j++) 
                    { 
                        s1 = data[i2, j]; 
                        p1 = s1.Split(','); 
                        if (p1[4] != "0")//当step的时间不为零 
                        { 
                            //step[n] = p1[2]; 
                            stepbts[n].Text = p1[2]; 
                            temps[n].Text = p1[3]; 
                            times[n].Text = p1[4]; 
                            n++; 
                          
                        } 
for (int i2 = 0; i2 < 6 &&n <6; i++) 
==> for (int i2 = 0; i2 < 6 &&n <6; i2++)PS: n在哪里申明并初始化的？ 

Answer 16

就是之前声明了下INT N=0;