正则表达式问题

Question

<[MultiRecords> qwewq
                <[MultiRecords>                 qwewqqwewq<[MultiRecords>                 qwewq</MultiRecords]>                </MultiRecords]>
                </MultiRecords]>
<[MultiRecords> qwewq
                <[MultiRecords>                 qwewqqwewq<[MultiRecords>                 qwewq</MultiRecords]>                </MultiRecords]>
                </MultiRecords]>
解析后的结果是1：<[MultiRecords> qwewq
                <[MultiRecords>                 qwewqqwewq<[MultiRecords>                 qwewq</MultiRecords]>                </MultiRecords]>
                </MultiRecords]>
2：<[MultiRecords> qwewq
                <[MultiRecords>                 qwewqqwewq<[MultiRecords>                 qwewq</MultiRecords]>                </MultiRecords]>
                </MultiRecords]>
我写的是<\[MultiRecords>((.|\n)*)<\/MultiRecords\]>，把所有的一次全部取出来了。不正确！

Answer 1

@"(?s)<\[MultiRecords>(.*?)<\/MultiRecords\]>"

Answer 2

源字符串：
<[MultiRecords> qwewq 
                <[MultiRecords>                 qwewqqwewq <[MultiRecords>                 qwewq </MultiRecords]>                 </MultiRecords]> 
                </MultiRecords]> 
<[MultiRecords> qwewq 
                <[MultiRecords>                 qwewqqwewq <[MultiRecords>                 qwewq </MultiRecords]>                 </MultiRecords]> 
                </MultiRecords]> 
想要的结果是：1. <[MultiRecords> qwewq 
                <[MultiRecords>                 qwewqqwewq <[MultiRecords>                 qwewq </MultiRecords]>                 </MultiRecords]> 
                </MultiRecords]> 
2： <[MultiRecords> qwewq 
                <[MultiRecords>                 qwewqqwewq <[MultiRecords>                 qwewq </MultiRecords]>                 </MultiRecords]> 
                </MultiRecords]> 

Answer 3

如果要取最内层的：
@"(?si)<\[MultiRecords>((?!<\[MultiRecords>).*?)<\/MultiRecords\]>"

Answer 4

非贪婪循环一次，可以一次取一个的
string tmp;
 foreach (Match match in Regex.Matches(NewsString, "(?i:src<\[MultiRecords>((.|\n)*) <\/MultiRecords\]>",RegexOptions.IgnoreCase))
{
                     tmp = match.Value;
//...
}

Answer 5

2楼的结果是：<[MultiRecords> qwewq
                <[MultiRecords>                 qwewqqwewq<[MultiRecords>                 qwewq</MultiRecords]>
和
<[MultiRecords> qwewq
                <[MultiRecords>                 qwewqqwewq<[MultiRecords>                 qwewq</MultiRecords]>
少了</MultiRecords]> 
                </MultiRecords]> ，你用非贪婪的，所有没有这两个。

Answer 6

"<[MultiRecords[^>]*>[^<>]*(((?'Open'<[MultiRecords[^>]*>)[^<>]*)+((?'-Open'</MultiRecords]>)[^<>]*)+)*(?(Open)(?!))</MultiRecords]>"

Answer 7

using System; 
using System.Text.RegularExpressions;class A
{ 
  static void Main()
  {
    string input = @"<[MultiRecords> qwewq 
                <[MultiRecords>                 qwewqqwewq <[MultiRecords>                 qwewq </MultiRecords]>                 </MultiRecords]> 
                </MultiRecords]> 
<[MultiRecords> qwewq 
                <[MultiRecords>                 qwewqqwewq <[MultiRecords>                 qwewq </MultiRecords]>                 </MultiRecords]> 
                </MultiRecords]>";
    string pattern = @"(?six)
<\[MultiRecords>   # 头
  (?>
    [^<>]+
    |
    <\[MultiRecords>(?<Depth>)
    |
    </MultiRecords\]>(?<-Depth>)
  )*
  (?(Depth)(?!))
</MultiRecords\]>  # 尾  
";
    int i = 0;
    foreach (Match m in Regex.Matches(input, pattern))
    {
      Console.WriteLine("------ 第{0}个匹配 -------\n{1}\n", ++i, m);
    }
  }
} 
/* 程序输出：
------ 第1个匹配 -------
<[MultiRecords> qwewq 
                <[MultiRecords>                 qwewqqwewq <[MultiRecords>                 qwewq </MultiRecords]>                 </MultiRecords]> 
                </MultiRecords]>------ 第2个匹配 -------
<[MultiRecords> qwewq 
                <[MultiRecords>                 qwewqqwewq <[MultiRecords>                 qwewq </MultiRecords]>                 </MultiRecords]> 
                </MultiRecords]>
*/